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hodyreva [135]
3 years ago
15

The biology club has 18 members 3 girls and 15 boys.What is the ratio of girls to boys in the biology club?

Mathematics
1 answer:
VashaNatasha [74]3 years ago
6 0
A.1:5 because 3 came first and 3:15 3÷3=1 15÷3=5 Therefore the answer is =1:5
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Can the sides of a triangle have length 1,3 and 5
Katen [24]

Answer:

No.

Step-by-step explanation:

The two smallest sides must be greater than the biggest side when added up in order to form a complete triangle.

1+3 is 4, which is less than five, so the triangle wouldn't be connected.

Essentially, imagine a triangle where one line is too short to reach the other two, which is what was just explained--the smallest sides must add up to be greater than the biggest side in order to form a complete triangle.

8 0
3 years ago
In 1990 four towns had the same population. Since then, the population of town 1 grew by a factor of 1.02, the population of tow
Alborosie

Answer: Town 1

Step-by-step explanation:

Town 1's population is growing at a factor of 1.02 which means that it is increasing by 2% a year.

Town 2 is growing at a factor of 0.999 which means that it is decreasing at a rate of:

= 1 - 0.999

= 0.1%

Town 3's population is increasing by 150 a year and town 4 is 200 people a year.

Town 1 will eclipse them all eventually because it is <u>growing proportionally at 2%</u>.

Towns 3 and 4 will eventually see 150 and 200 people fall below 2% of their town's population which means they will be growing at a slower rate than Town 1.

4 0
3 years ago
f a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8%, can we use the Normal a
Troyanec [42]

Answer:

Probability of at least 50 obese individuals in our sample is 0.92364 .

Step-by-step explanation:

We are given that a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8% .

Let X = Number of obese individuals

Firstly, X ~ Binom(n=300,p=0.198)

For approximating binomial distribution into normal distribution, firstly we have to calculate \mu and \sigma^{2} .

Mean of Normal distribution, \mu = n * p = 300 * 0.198 = 59.4

Variance of Normal distribution,\sigma^{2} = n * p * (1-p) = 300 *0.198 *0.802 = 47.64

So, now X ~ N(\mu = 59.4 , \sigma^{2} = 47.64)

The standard normal z score distribution is given by;

                     Z = \frac{X-\mu}{\sigma} ~ N(0,1)

So, probability of at least 50 obese individuals in our sample = P(X >= 50)

  P(X >= 50) = P(X > 49.5)  {using continuity correction}

  P(X > 49.5) = P( \frac{X-\mu}{\sigma} > \frac{49.5 - 59.4}{6.9} ) = P(Z > -1.43) = P(Z < 1.43) = 0.92364

Therefore, required probability is 0.92364 .

8 0
3 years ago
I need answers ASAP! Thanks!
Daniel [21]

Step-by-step explanation:

43. P, U

44. 7

53. Airplanes can be traveling on different planes, one plane above the other. Cars on the same intersection are on the same plane.

55

a. You can choose (4 * 3 * 2)/(3 * 2) = 4 groups of 3 points in which order does not matter.

One of those combinations does not have K, so 3 combinations of the 4 have K.

p = 3/4

b. p = 1 since any three points are always coplanar.

3 0
3 years ago
Simplify x^2+ 5x + 4 over <br> x+4
harkovskaia [24]

Answer:

x+1

Step-by-step explanation:

6 0
3 years ago
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