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aalyn [17]
3 years ago
6

Marty ate 4/6 of his pizza Luis ate 5/6 of his. Marty ate more pizza than Luis how is that possible

Mathematics
2 answers:
Ksivusya [100]3 years ago
8 0
If you simplify 4/6, it comes out to 2/3. Basically because of the fraction size, it looks like Mary ate more because of the simplified denominator of 4/6 is smaller. Luis actually ate more pizza than Mary.
Ugo [173]3 years ago
7 0
It is not posible because 4/6 is lesser than 5/6
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1919=0+1+0+1=2

Step-by-step explanation:

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2 years ago
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valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

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<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
2 years ago
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tekilochka [14]
B.) would be correct
(x,y)
x=-5
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