soh cah toa
that is the saying I use
we will use cah
c is cos
a is ajacent
h is hypotinuse
to find cos K we need to do
adjacent / hypotenuse
can you do that and write it in the comments
Answer:
y=8/7x+5
Step-by-step explanation:
y=mx+b but m is your slope and b is your y intercept.
Answer:
Point C
Step-by-step explanation:
We want to reflect across the x axis
That means the y coordinate changes sign
Z = ( 5 1/2 , 3)
Z' = ( 5 1/2 , -3)
That is point C
Answer: r = -5/18
Step-by-step explanation: You solve -3(1+6r)+12=14
-3-18r+12=14 (When distributed)
-18r+9=14
-18r=5
r=-5/18
Given that a unshaded rectangle is inscribed in a shaded circle, the area of the shaded region is 72.67m².
Given that a unshaded rectangle is inscribed in a shaded circle.
- Diameter of the circle d = 13m
- Radius r = d/2 = 13m/2 = 6.5m
- Dimension of length of the rectangle l = 12m
- Dimension of width of the rectangle w = 5m
- Area of the shaded region As = ?
First we calculate the area of the shaded circle.
A = πr² = π × ( 6.5m )²
A = 132.665m²
Area of the shaded circle is 132.665m².
Area of the unshaded rectangle will be;
A = l × w
A = 12m × 5m
A = 60m²
Area of the unshaded rectangle is 60m².
Now, area of the shaded region will be;
= Area of the shaded circle - Area of the unshaded rectangle
= 132.665m² - 60m²
= 132.665m² - 60m²
= 72.67m²
Given that a unshaded rectangle is inscribed in a shaded circle, the area of the shaded region is 72.67m².
Learn more about area polygons here: brainly.com/question/22590672
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