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baherus [9]
3 years ago
13

Can someone plz help me w this

Mathematics
2 answers:
allochka39001 [22]3 years ago
6 0
4x2 is 16x
(3x-1, 3-x : 2x+2)
18x+11
Rasek [7]3 years ago
3 0
(3x - 1)(3 -x)+x^2 + 19

a)
(3x - 1)(3 -x)+x^2 + 19
=9x - 3x^2 - 3 + x + x^2 + 19
= -2x^2 + 10x + 16

b) evaluate at x = 2

-2x^2 + 10x + 16
= -2 (2^2) + 10(2) + 16
= -8 + 20 + 16
= 28

c) 
from part (a) 
-2x^2 + 10x + 16

= -2 (x^2 - 5x - 8) (complete factor)
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son4ous [18]
The chain rule states that

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

Since \ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2), you have

\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}
\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}
\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}

and

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\dfrac{\mathrm dy}{\mathrm dt}=-\sin t
\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t

Also, since x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t, the derivative is

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}
\dfrac{\mathrm dw}{\mathrm dt}=\tan t
4 0
3 years ago
Brent is trying to figure out the relationship between the number of times his friends post on social media and their grade poin
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The given graph shows the relationship between the social media posts and grade point average of different students in Brent's class.

From the given graph, we can say that the grade point average of students decrease with increase in number of their social media posts.  

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Hence, option D is correct i.e. Strong Negative Correlation.

5 0
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Step-by-step explanation:

20 each because it's like tgat

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Here, we want to check for the relationship between the image and its pre-image

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As we can see, the pre-image is not similar

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Thus, we have that;

No, the image is not similar to the pre-image as the translations applied to both coordinates are not same

The pre-image was transformed by dilating the x-coordinate of the pre-image by 3 units while the y-coordinate was transformed by dilating the y-coordinate of the pre-image by 3 and translating it upward by 5 units

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How to write a linear equation in slop intercept form
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Second one

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