Answer:
The speed is 20.8 m/s
Step-by-step explanation:
If a projectile ascends vertically, and after 3 seconds it reaches its maximum height, calculate the velocity that it carries to the middle of its downward trajectory
Let the maximum height is h and initial velocity is u.
From first equation of motion
v = u + at
0 = u - g x 3
u = 3 g.....(1)
Use third equation of motion

Let the speed at half the height is v'.

I can't put the whole screenshot in here
It already shows that AB is 49°
in order to find ABC you must first find BC
360 - (AC + AB) = BC
360 - 156 = BC
204° = BC
NOW add BC with AB
49 + 204
253
angle ABC is 253°
now to find BAC add AB and AC
49 + 107 = 156°
angle BAC is 156°
FINALLY to find ACB add AC and CB
107 + 204
311°
angle ACB is 311°
Answer:
Width 10y^6 units
Length 7y^2+3 units
Step-by-step explanation: