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ohaa [14]
3 years ago
10

Find two consecutive whole numbers that lies between 134

Mathematics
1 answer:
Finger [1]3 years ago
5 0
I think the answer is 11 and 12 but my calculations could be incorrect.

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For the following exercises, evaluate the function at the indicated values:
STALIN [3.7K]

Answer:

The evaluated function for the indicated values is given below.

The value of f(-3) is 20 .

The value of f(2) is 10 .

The value of f(-a) is $2|-3 a-1|$.

The value of -f(a) is $-2|3 a-1|$.

The value of f(a+h) is $2|3 a+3 h-1|$.

Step-by-step explanation:

A function $f(x)=2|3 x-1|$ is given.

It is required to evaluate the function at $f(-3) ; f(2) ; f(-a) ;-f(a) ; f(a+h)$.

To evaluate the function, substitute the indicated values in the given function to determine the output values and simplify the expression.

Step 1 of 5

The given function is $f(x)=2|3 x-1|$.

To evaluate the function at f(-3), substitute -3 in the given function f(x)=2|3 x-1|$\\ $f(-3)=2|3(-3)-1|$\\ $f(-3)=2|-9-1|$\\ $f(-3)=2|-10|$\\ $f(-3)=2(10)$\\ $f(-3)=20$

Step 2 of 5

To evaluate the function at $f(2)$, substitute 2 in the given function.

f(x)=2|3 x-1|$\\ $f(2)=2|3(2)-1|$\\ $f(2)=2|6-1|$\\ $f(2)=2(5)$\\ $f(2)=10$

Step 3 of 5

To evaluate the function at f(-a), substitute -a in the given function.

$$\begin{aligned}&f(x)=2|3 x-1| \\&f(-a)=2|3(-a)-1| \\&f(-a)=2|-3 a-1|\end{aligned}$$

Step 4 of 5

To evaluate the function at -f(a), substitute a in the given function.

f(x)=2|3 x-1|$\\ $-f(a)=-2|3(a)-1|$\\ $-f(a)=-2|3 a-1|$

Step 5 of 5

To evaluate the function at f(a+h), substitute a+h in the given function. $f(x)=2|3 x-1|$

$$\begin{aligned}&f(a+h)=2|3(a+h)-1| \\&f(a+h)=2|3 a+3 h-1|\end{aligned}$$

7 0
2 years ago
1-5 PLEASE SHOW WORK!! I will mark brainliest and a lot of points!!
madreJ [45]

Answer:

Step-by-step explanation:

2. -x+4+3x+2=2x+6

3. -x-2-4x-3=-5x-5

4.-36-24=-60

5.  9+10-6-6=7

5 0
3 years ago
What Is thee error and the solution​
Readme [11.4K]

Answer:

X=5

Step-by-step explanation:

Multiply by 3 first

4 0
3 years ago
Which domain restrictions apply to this rational expression? x2 4x 4x2−4 select each correct answer.
rosijanka [135]

Because domain restrictions apply to this rational expression, x cannot be equal to {-2, 2}.

<h3>What is domain?</h3>

Domain restrictions are any points in the domain where the function will not have a value. This basically means that there is a point in the function where x will not work.

For the numerator, any value of x will suffice. We can have a value of 0 in the numerator, or a positive, negative, or decimal number.

However, the denominator cannot be equal to zero. This is due to the fact that a fraction bar represents division, and we cannot divide by zero.

Here,

x²-4=0

Add 4 to both sides:

x²-4+4 = 0+4

x² = 4

Take the square root of both sides:

√x² = √4

x = 2 or x = -2

The x cannot be equal to {-2, 2} as domain restrictions apply to this rational expression.

To know more about domain,

brainly.com/question/10238709

#SPJ4

7 0
1 year ago
Find the equation of the axis of symmetry for the parabola y = x^2 + 5x.
viktelen [127]
Axis of symmetry =-b/2a
so subsitiute
a=1,b=5
-5/2
i believe thr axis of symmetry is at -2.5
6 0
4 years ago
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