Answer:
B. You have to distribute properties. So you distribute the exponent 5 to both the 6 & the 9
<span>In triangle WXZ,
Line WY is an altitude (as shown in the attached picture)
Now, it is given that:
</span><span>If ΔYWZ ~ ΔYXW
</span>∠WXY = ∠WZY
<span>
Then, we can also conclude
</span>∠WYX = ∠WYZ = 90°....(1) (because WY is the altitude)
Now, in any triangle, the sum of all the three angles is 180.
In triangle, WXY, ∠WYX = 90° (From 1)
Therefore, WXY + XWY = 90°
Similarly, in WZY.
Hence, we conclude that XWZ is a right angle.
To solve this problem, we simply use the equation of
volume for hollow cylinders:
V = π h (R^2 – r^2)
where V is volume, h is height = 10, R is outer radius =
8.4/2 = 4.2, r is inner radius = 6/2 = 3
V = π (10) (4.2^2 – 3^2)
<span>V = 86.4π = 271.43 mm^3</span>
Step 1
Find the area of one equilateral triangle
Applying the law of sines

in this problem
a=b=7 cm
C=60 degrees
so

cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
cm²
therefore
the answer is the option
73.5 sqrt 3cm²