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Anastaziya [24]
3 years ago
5

What is 2 + 1 = ? is it 3 or is it 3 because i dont know​

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
7 0

ANSWER

3

Explanation

2+1=3

Vesnalui [34]3 years ago
3 0

Answer: 4

Step-by-step explanation:

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Please be quick! I need this as soon as possible!
PolarNik [594]

Answer:

35

Step-by-step explanation:

40*3=120

120-85=35

5 0
3 years ago
Given three positive integers a, b and c such that a² + b² - c² = 1. Let the number of triangles formed with sides a, b and c wi
Akimi4 [234]

Answer:

Step-by-step explanation:

Count pairs (a, b) whose sum of squares is N (a^2 + b^2 = N)

Given a number N, the task is to count all ‘a’ and ‘b’ that satisfy the condition a^2 + b^2 = N.

Note:- (a, b) and (b, a) are to be considered as two different pairs and (a, a) is also valid and to be considered only one time.

Examples:

Input: N = 10

Output: 2

1^2 + 3^2 = 9

3^2 + 1^2 = 9

Input: N = 8

Output: 1

2^2 + 2^2 = 8

8 0
4 years ago
Find x in this proportion.<br> 5/2x=25/4<br> x=__?<br> 2/5<br> 5/2<br> 4/5<br> 8/5
8_murik_8 [283]
Correct answer is A.

\frac{5}{2x} = \frac{25}{4} &#10;\\&#10;\\2x\times 25=5\times 4&#10;\\50x=20&#10;\\&#10;\\x= \frac{20}{50}= \frac{2}{5}
8 0
3 years ago
Read 2 more answers
What is the volume of the prism?<br><br> 14 m3<br> 24 m3<br> 30 m3<br> 44 m
geniusboy [140]

Answer:

the answer is 24 m3

                                             

6 0
3 years ago
For the following exercises, determine whether the relation is a function.
elixir [45]

Answer:

The given relation $\{(a, b),(c, d),(e, d)\}$ is a function.

Step-by-step explanation:

A relation $\{(a, b),(c, d),(e, d)\}$ is given.

It is required to determine whether the given relation is a function.

To determine whether the given function is a relation, identify the domain and range and then check whether the given relation is a function.

Step 1 of 1

The given relation is {(a, b),(c, d),(e, d)}.

The set of the first components of each ordered pair is called the domain.

From the relation, the domain is {a, c, e}.

The set of the second components of each ordered the range.

From the relation, the range is {b, d, d}.

The given relation is a function. But it is not a one-to-one function.

7 0
2 years ago
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