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masya89 [10]
3 years ago
12

In the figure, triangle ABC is congruent to triangle ADC . If the square ABCD is dilated by a factor of 2 to form A'B'C'D', what

is the ratio of the area of A'B'C'D' to the area of ABCD?
a.) 2 : 1

b.) 3 : 1

c.) 4 : 1

d.) 5 : 1
Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
Its 4:1 hope this helps you out.
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Is 5 a solution to the equation 2x^2 + 10 = 60 yes or no
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2(5)^2+10
2(25)+10
50+10
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On awall of dimension10.5m long and 8.5 m wide, a square shaped wall posture is stuck at the centre whose one side measures2.5m.
tangare [24]

Answer:

₹996

Step-by-step explanation:

Area painted = area of wall - area of wall posture

Area of a rectangle = length x breadth

= 10.5m x 8.5m = 89.25m^2

Area of a square

length x length

2.5m x 2.5m = 6.25m^2

Area painted =  89.25m^2 -  6.25m^2 = 83m^2

Total cost of area painted = 83m^2 x 12 = 996

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These two polygons are similar. ​
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yea........ hi how you doinn

4 0
3 years ago
F (x) = √2X-6<br> What is f(5)?
inessss [21]

Answer:

f(5) = 2

Step-by-step explanation:

<u>Given: </u>

  • Function f(x) = \sqrt{2x - 6}

<u>For x=5 :</u>

  • f(5) = \sqrt{2*5 - 6} = \sqrt{4} = 2
7 0
3 years ago
List x1, x2, x3, x4 where xi is the left endpoint of the four equal intervals used to estimate the area under the curve of f(x)
n200080 [17]

Answer:

Option A. 4, 4.5, 5, 5.5

Step-by-step explanation:

Left point: a=x=4

Right point: b=x=6

Range: r=b-a→r=6-4→r=2

Width of each of the four equal intervals: w=2/4→w=0.5

The first left endpoint is x1=a→x1=4

The second left endpoint is x2=x1+w→x2=4+0.5→x2=4.5

The third left endpoint is x3=x2+w→x3=4.5+0.5→x3=5

The fourth left endpoint is x4=x3+w→x4=5+0.5→x4=5.5

Then, the list is: x1, x2, x3, x4 = 4, 4.5, 5, 5.5

4 0
3 years ago
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