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3 years ago

Is 5 a solution to the equation 2x^2 + 10 = 60 yes or no

Mathematics

2 answers:

cricket20 [7]3 years ago

8 0

2(5)^2+10
2(25)+10
50+10
60
Yes

notka56 [123]3 years ago

7 0

Hello :
yes : 2(5)² +10 = 60
50+10=60... ( right )

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Find the measure of the angle indicated. ? 850 A) 850 C) 80° B) 65° D) 97°

antoniya [11.8K]

A

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2 years ago

How many 6-digit numbers can be created using8, 0, 1, 3, 7, and 5 if each number is used only once?

Ludmilka [50]

Answer:

600 numbers

Step-by-step explanation:

For six-digit numbers, we need to use all digits 8,0,1,3,7,5 each once.

However, 0 cannot be used as the first digit, because it would make a 5-digit number.

Therefore

there are 5 choices for the first digit (exclude 0)

there are 5 choices for the first digit (include 0)

there are 4 choices for the first digit

there are 3 choices for the first digit

there are 2 choices for the first digit

there are 1 choices for the first digit

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3 years ago

Can you Afford to Enlarge this?You each want to have a 3" X 5' picture ofprinted so that you canput it on your dartboard. It cos

Marizza181 [45]

Given:

$\text{ Dimension = 3}\times5$

Sol:

Area of picture is:

$\begin{gathered} =\text{ length}\times\text{ Width} \\ \\ =15 \end{gathered}$

If the cost $10 per square inch then price of 15 square inch is:

$\begin{gathered} =15\times10 \\ \\ =150 \end{gathered}$

If the quadruple of dimension that mean:

$\begin{gathered} \text{ l ength = 4 length} \\ \\ Width\text{ = 4 width} \end{gathered}$

So area is:

$\begin{gathered} A=4\text{ length}\times4\text{ Width} \\ \\ A=4(15) \\ \\ A=60 \end{gathered}$

So price is:

$\begin{gathered} =60\times10 \\ \\ =600 \end{gathered}$

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1 year ago

Oliver and his three friends equally share the cost of an Uber to go to the movies. The total Uber fare is $12.80. How much mone

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3 dollars a d 20 cents I hope

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3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

ddd [48]

Answer:

$f'(x) = 4x^2 - 3$ for $x \le -3$

Step-by-step explanation:

See attachment for proper question

Given

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

For

$x \ge -3$

Required

Determine the inverse function

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

Replace f(x) with y

$y = -\frac{1}{2}\sqrt{x + 3}$

Swap the positions of x and y

$x = -\frac{1}{2}\sqrt{y + 3}$

Multiply both sides by -2

$-2 * x =-2 * -\frac{1}{2}\sqrt{y + 3}$

$-2x =\sqrt{y + 3}$

Square both sides

$(-2x)^2 =(\sqrt{y + 3})^2$

$4x^2 =y + 3$

Make y the subject

$y = 4x^2 - 3$

The inverse has been solved. So, we need to replace y with f'(x)

$f'(x) = 4x^2 - 3$

Next, is to determine the interval

$x \ge -3$

Change inequality to $\le$

$x \le -3$

Hence, the inverse function is:

$f'(x) = 4x^2 - 3$ for $x \le -3$

7 0

3 years ago