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slega [8]
3 years ago
7

Is 5 a solution to the equation 2x^2 + 10 = 60 yes or no

Mathematics
2 answers:
cricket20 [7]3 years ago
8 0
2(5)^2+10
2(25)+10
50+10
60
Yes
notka56 [123]3 years ago
7 0
Hello : 
yes : 2(5)² +10 = 60
50+10=60... ( right ) 

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Find the measure of the angle indicated.<br> ?<br> 850<br> A) 850<br> C) 80°<br> B) 65°<br> D) 97°
antoniya [11.8K]
A


They are Corresponding angles

Mark brainliest please
8 0
2 years ago
How many 6-digit numbers can be created using8, 0, 1, 3, 7, and 5 if each number is used only once?
Ludmilka [50]

Answer:

600 numbers

Step-by-step explanation:

For six-digit numbers, we need to use all digits 8,0,1,3,7,5 each once.

However, 0 cannot be used as the first digit, because it would make a 5-digit number.

Therefore

there are 5 choices for the first digit (exclude 0)

there are 5 choices for the first digit (include 0)

there are 4 choices for the first digit

there are 3 choices for the first digit

there are 2 choices for the first digit

there are 1 choices for the first digit

for a total of 5*5*4*3*2*1 = 600 numbers

6 0
3 years ago
Can you Afford to Enlarge this?You each want to have a 3" X 5' picture ofprinted so that you canput it on your dartboard. It cos
Marizza181 [45]

Given:

\text{ Dimension = 3}\times5

Sol:

Area of picture is:

\begin{gathered} =\text{ length}\times\text{ Width} \\  \\ =15 \end{gathered}

If the cost $10 per square inch then price of 15 square inch is:

\begin{gathered} =15\times10 \\  \\ =150 \end{gathered}

If the quadruple of dimension that mean:

\begin{gathered} \text{ l ength = 4 length} \\  \\ Width\text{ = 4 width} \end{gathered}

So area is:

\begin{gathered} A=4\text{ length}\times4\text{ Width} \\  \\ A=4(15) \\  \\ A=60 \end{gathered}

So price is:

\begin{gathered} =60\times10 \\  \\ =600 \end{gathered}

3 0
1 year ago
Oliver and his three friends equally share the cost of an Uber to go to the movies. The total Uber fare is $12.80. How much mone
PIT_PIT [208]
3 dollars a d 20 cents I hope
5 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
ddd [48]

Answer:

f'(x) = 4x^2 - 3 for x \le -3

Step-by-step explanation:

See attachment for proper question

Given

f(x) = -\frac{1}{2}\sqrt{x + 3}

For

x \ge -3

Required

Determine the inverse function

f(x) = -\frac{1}{2}\sqrt{x + 3}

Replace f(x) with y

y = -\frac{1}{2}\sqrt{x + 3}

Swap the positions of x and y

x = -\frac{1}{2}\sqrt{y + 3}

Multiply both sides by -2

-2 * x =-2 *  -\frac{1}{2}\sqrt{y + 3}

-2x =\sqrt{y + 3}

Square both sides

(-2x)^2 =(\sqrt{y + 3})^2

4x^2 =y + 3

Make y the subject

y = 4x^2 - 3

The inverse has been solved. So, we need to replace y with f'(x)

f'(x) = 4x^2 - 3

Next, is to determine the interval

x \ge -3

Change inequality to \le

x \le -3

Hence, the inverse function is:

f'(x) = 4x^2 - 3 for x \le -3

7 0
3 years ago
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