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Kruka [31]
2 years ago
6

Which object has a greater surface area: a cube with edges

Mathematics
1 answer:
Mashcka [7]2 years ago
8 0

Answer:

cylinder

Step-by-step explanation:

SA(cube) = 6 cm³

SA(cyl) = 36.11 cm³

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I need the answers to this. I have no clue at all how to do this!
Ber [7]

Answer:

Opens: Up

Maximum or minimum: Minimum is -4

Describe the translation: A vertical shift of 4 downwards


4 0
2 years ago
It's multiplication i know but it's a tricky one so help my soul
pav-90 [236]

Answer: -8x^3y^2  (choice B)

The coefficients multiply to 4 times -2 = -8

the x terms multiply to x^2 times x = x^(2+1) = x^3

The y terms multiply to y times y = y^(1+1) = y^2

So that's how I ended up with -8x^3y^2

7 0
3 years ago
Let R = [ 0 , 1 ] × [ 0 , 1 ] R=[0,1]×[0,1]. Find the volume of the region above R R and below the plane which passes through th
Bond [772]

The three vectors \langle0,0,1\rangle, \langle1,0,8\rangle, and \langle0,1,9\rangle each terminate on the plane. We can get two vectors that lie on the plane itself (or rather, point in the same direction as vectors that do lie on the plane) by taking the vector difference of any two of these. For instance,

\langle1,0,8\rangle-\langle0,0,1\rangle=\langle1,0,7\rangle

\langle0,1,9\rangle-\langle0,0,1\rangle=\langle0,1,8\rangle

Then the cross product of these two results is normal to the plane:

\langle1,0,7\rangle\times\langle0,1,8\rangle=\langle-7,-8,1\rangle

Let (x,y,z) be a point on the plane. Then the vector connecting (x,y,z) to a known point on the plane, say (0, 0, 1), is orthogonal to the normal vector above, so that

\langle-7,-8,1\rangle\cdot(\langle x,y,z\rangle-\langle0,0,1\rangle)=0

which reduces to the equation of the plane,

-7x-8y+z-1=0\implies z=7x+8y+1

Let z=f(x,y). Then the volume of the region above R and below the plane is

\displaystyle\int_0^1\int_0^1(7x+8y+1)\,\mathrm dx\,\mathrm dy=\boxed{\frac{17}2}

6 0
2 years ago
explain how it is possible that all proportional relationships are linear functions but not all linear functions are proportiona
OLEGan [10]

Proportional and linear functions are almost identical in form. The only difference is the addition of the “b” constant to the linear function. Indeed, a proportional relationship is just a linear relationship where b = 0, or to put it another way, where the line passes through the origin (0,0).

You’re welcome

6 0
3 years ago
If f(x)=2x-4, what would be the answer if f(3)-1??
Vinil7 [7]

Answer:

1

Step-by-step explanation:

We have the function

f(x) = 2x - 4

and we want to know the value of f(3) - 1.

The first step is to find f(3) ; we can subtract 1 from it at the end! But what does f(3) mean?

Basically, we're saying <em>"what is the value of the function when </em>x = 3<em> ?"</em>

So, we simply replace x with 3 in the function, and we get:

f(3) = 2\times 3 - 4 = 2.

Finally, we subtract 1 to find f(3) - 1 = 1.

3 0
2 years ago
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