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olasank [31]
3 years ago
12

Determine the value of a 10 year old car that costs $24,500 new and depreciates by 9% every year

Mathematics
2 answers:
son4ous [18]3 years ago
7 0
First, we need to know how much the car depreciates each year. Multiply the price of the car by the percentage.

We can turn 9% into a decimal by moving the decimal point two places to the right.

9% = .09

24500 * .09 = 2205

Multiply the product by the amount of years you want to predict the price at.

2205 * 10 = 22050

Subtract that from the original price of the car.

24500 - 22050 = 2450

The value of a 10 year old car that costs $24500 and depreciates 9% every year will cost $2450.
Dmitry [639]3 years ago
7 0
2450 is the correct answer
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4 0
3 years ago
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The following data shows the quarterly profit (in thousands of dollars) made by a particular company in the past 3 years.
laiz [17]

Answer:

208.82 ; 61.33

Step-by-step explanation:

Given the data:

Year Quarter Profit ($1000s)

1 1 45

1 2 51

1 3 72

1 4 50

2 1 49

2 2 45

2 3 79

2 4 54

3 1 42

3 2 58

3 3 70

3 4 56

The 3 period moving average :

Yr Qtr Profit ($1000s)Pt ____ Ft ____ e=(PT-Ft)²

1 _ 1 ___45 __

1 _ 2 __ 51 __

1 _ 3 __ 72 __

1 _ 4 __ 50 ______________56 ____ 36

2 _ 1 __ 49 ______________57.67__ 75.17

2 _ 2__ 45 ______________57 ____ 144

2 _ 3__ 79 ______________48 ____961

2 _ 4__ 54 ______________57.67 _ 13.47

3 _ 1__ 42 ______________59.33__300.33

3 _2 __ 58 ______________58.33__ 0.11

3 _ 3__ 70 ______________51.33__ 348.57

3 _ 4 __56 ______________56.67__0.45

MSE = Σ(Pt - Ft)² ÷ n

MSE = (36+75.17+144+961+13.47+300.33+0.11+348.57+0.75) ÷ 9

= 208.82

Forecast for next quarter :

(58 + 70 + 56) / 3 = 184 /3 = 61.33

8 0
3 years ago
For somebody that need it
djverab [1.8K]

Answer:

is there a question in this? lol, if not, tyy!!

Step-by-step explanation:

4 0
3 years ago
Find the solution of the given initial value problems in explicit form. Determine the interval where the solutions are defined.
natali 33 [55]

Answer:

The solution of the given initial value problems in explicit form is y=x-x^2-2  and the solutions are defined for all real numbers.

Step-by-step explanation:

The given differential equation is

y'=1-2x

It can be written as

\frac{dy}{dx}=1-2x

Use variable separable method to solve this differential equation.

dy=(1-2x)dx

Integrate both the sides.

\int dy=\int (1-2x)dx

y=x-2(\frac{x^2}{2})+C                  [\because \int x^n=\frac{x^{n+1}}{n+1}]

y=x-x^2+C              ... (1)

It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.

-2=1-(1)^2+C

-2=1-1+C

-2=C

The value of C is -2. Substitute C=-2 in equation (1).

y=x-x^2-2

Therefore the solution of the given initial value problems in explicit form is y=x-x^2-2 .

The solution is quadratic function, so it is defined for all real values.

Therefore the solutions are defined for all real numbers.

4 0
3 years ago
a store sells 1/3 pound of asparagus for $.75. You need to buy 5 pounds How much will u pay? Draw a modell or explain step by st
lana66690 [7]

Answer:

$11.25


Step-by-step explanation: multiply .75 by 3 then multiply that answer by 5 and get your answer.


3 0
3 years ago
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