How do you convert 20/12 to a proper fraction

Can anybody help? Exponential Functions

lana [24]

................................................................................................

4 0

3 years ago

Last year, Susan had 10,000 to invest. She invested some of it in an account that paid 6%

katrin2010 [14]

Answer:

In the account that paid 6% Susan invest $\$6,000$

In the account that paid 5% Susan invest $\$4,000$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

Part a) account that paid 6% simple interest per year

in this problem we have

$t=1\ years\\ P=\$x\\r=0.06$

substitute in the formula above

$I1=x(0.06*1)$

$I1=0.06x$

Part b) account that paid 5% simple interest per year

in this problem we have

$t=1\ years\\ P=\$10,000-\$x\\r=0.05$

substitute in the formula above

$I2=(10,000-x)(0.05*1)$

$I2=500-0.05x$

we know that

$I1+I2=\$560$

substitute and solve for x

$0.06x+500-0.05x=560$

$0.01x=560-500$

$0.01x=60$

$x=\$6.000$

therefore

In the account that paid 6% Susan invest $\$6,000$

In the account that paid 5% Susan invest $\$4,000$

6 0

3 years ago

In order to avoid staying after work, a quality control analyst inspects the first 100 items produced that day. Which sampling m

mr_godi [17]

Based on the given scenario above wherein the quality control analyst just inspects the first 100 items produced that day in order to avoid staying after work, the sampling method that she used is the CONVENIENCE SAMPLING METHOD. Hope this helps.

3 0

3 years ago

Read 2 more answers

In a population distribution, a score of x=57 corresponds to z=-0.25 and a score of x=87 corresponds to z=1.25. Find the mean an

Serggg [28]

Here is dependence between scores and x-values:

$Z_i=\dfrac{X_i-\mu}{\sigma},$

where $\mu$ is the mean, $\sigma$ is standard deviation and i changes from 1 to 2.

1. When i=1, $Z_1=-0.25,\ X_1=57,$ then

$-0.25=\dfrac{57-\mu}{\sigma}.$

2. When i=2, $Z_2=1.25,\ X_2=87,$ then

$1.25=\dfrac{87-\mu}{\sigma}.$

Now solve the system of equations:

$\left\{\begin{array}{l}-0.25=\dfrac{57-\mu}{\sigma}\\ \\1.25=\dfrac{87-\mu}{\sigma}.\end{array}\right.$

$\left\{\begin{array}{l}-0.25\sigma=57-\mu\\ \\1.25\sigma=87-\mu.\end{array}\right.$

Subtract first equation from the second:

$1.25\sigma-(-0.25\sigma)=87-57,\\ \\1.5\sigma=30,\\ \\\sigma=20.$

Then

$1.25=\dfrac{87-\mu}{20},\\ \\87-\mu=25,\\ \\\mu=87-25=62.$

Answer: the mean is 62, the standard deviation is 20.

3 0

3 years ago

Read 2 more answers

Place each of the key aspects under the function it describes

melamori03 [73]

Answer:

range: {y: y ≥ 0} ⇒ h(x)

decreasing over(-∞ , 1) ⇒ h(x)

increasing over (-∞ , 0) ⇒ g(x)

range: {y: y ≤ 1} ⇒ g(x)

increasing over (1 , ∞) ⇒ h(x)

decreasing over(0 , ∞) ⇒ g(x)

Step-by-step explanation:

∵ h(x) = (x - 1)²

∴ Its vertex is (1 , 0)

∴ The parabola is opened upward

∴ The range: {y: y ≥ 0}

∴ It's decreasing over (-∞ , 1)

∴ It's increasing over (1 , ∞)

∵ g(x) = -(x - 1)(x + 1) = -(x² - 1) = -x² + 1

∴ Its vertex is (0 , 1)

∴ The parabola is opened downward

∴ The range: {y: y ≤ 1}

∴ It's increasing over (-∞ , 0)

∴ It's decreasing over (0 , ∞)

5 0

3 years ago

Read 2 more answers