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The given curve is --- y = x^5 + x^3 - 2x
<span>First derivative to this curve is y' = 5 x^4 + 3 x^2 - 2 </span>
<span>=> Slope (m) = 5 x^4 + 3 x^2 - 2 </span>
<span>For the minimum value of m we calculate dm/dx and put it = 0 </span>
<span>=> d( 5 x^4 + 3 x^2 - 2 ) / dx = 0 </span>
<span>=> 20 x^2 + 6 x = 0 </span>
<span>=> x ( 20 x + 6 ) = 0 </span>
<span>Turning values of x are 0 and - 6 / 20 = ( - 3 / 10 ) </span>
<span>At x = 0 , m = - 2 </span>
<span>and at x = - 3/10 </span>
<span>m = 5 x^4 + 3 x^2 - 2 </span>
<span>=> m = 5 ( - 3 / 10 )^4 + 3 ( - 3 / 10 )^2 - 2 = - 1.68 </span>
<span>Hence at turning points, the slope is minimum at x = 0 and is equal to = - 2 </span>
<span>MINIMUM VALUE OF THE SLOPE = - 2</span>
Answer: the answer is 7
Step-by-step explanation: add 9 to both sides, eliminating -9 so now you have 7x=49 divide both by 7 and you get x= 7 check it by inputing 7 for x, 7(7)-9=40
7(7)=49 next 49-9= 40
it checks out, so x= 7
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You have to multiply first and then be a bad bleep
