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Lelu [443]
3 years ago
15

Which number is in the solution set of this equation? 7x − 9 = 40

Mathematics
1 answer:
skad [1K]3 years ago
7 0

Answer: the answer is 7

Step-by-step explanation: add 9 to both sides, eliminating -9 so now you have 7x=49 divide both by 7 and you get x= 7 check it by inputing 7 for x, 7(7)-9=40

7(7)=49 next 49-9= 40

it checks out, so x= 7

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Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, proj,u
11Alexandr11 [23.1K]

Answer:

Take b = \frac{-17}{25}(7,1) as the projection of u onto v and w \frac{1}{25}(-31,217) as the vector such that b+w =u

Step-by-step explanation:

The formula of projection  of a vector u onto a vector v is given by

\frac{u\cdot v}{v\cdot v}v, where cdot is the dot product between vectors.

First, let b ve the projection of u onto v. Then

b = \frac{u\cdot v}{v\cdot v}v= \frac{-6\cdot 7+8\cdot 1}{7\cdot 7+1\cdot 1}(7,1) = \frac{-34}{50}(7,1) = \frac{-17}{25}(7,1)

We want a vector w, that is orthogonal to b and that b+w = u. From this equation we have that w = u-b = (-6,8)-\frac{-17}{25}(7,1)= \frac{1}{25}(-31,217)[/tex]

By construction, we have that w+b=u. We need to check that they are orthogonal. To do so, the dot product between w and b must be zero. Recall that if we have vectors a,b  that are orthogonal then for every non-zero escalar r,k the vector ra and kb are also orthogonal. Then, we can check if w and b are orthogonal by checking if the vectors (7,1) and (-31, 217) are orthogonal.

We have that (7,1)\cdot(-31,217) = 7\cdot -31 + 217 \cdot 1 = -217+217 =0. Then this vectors are orthogonal, and thus, w and b are orthogonal.

5 0
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Divide. (See image.) Please help!
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Answer is attached please look at it

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Answer:

Step-by-step explanation:

9x - 77 = 7x - 43

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x = 17

9(17) - 77 = 153 - 77 = 76

7(17) - 43 = 119 - 43 = 76

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z= 104

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Step-by-step explanation:

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