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Rudik [331]
3 years ago
8

Find the equation of a line in standard form that passes through the point (6, -2) and is perpendicular to 3x - 5y = 10.

Mathematics
1 answer:
iris [78.8K]3 years ago
7 0
Here is the solution, sorry if I’ve made an error

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sergey [27]
Hay 10 decímetros en un metro
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2 years ago
Why did the scientist make an exact duplicate of himself
SVETLANKA909090 [29]

This is a math riddle in which you can only discover the answer by cracking the given equations and each answer has the corresponding letters. Nonetheless, the solution to this is the scientist created an exact duplicate of himself because HE WAS JUST CLONING AROUND

3 0
3 years ago
Make a table showing the probability distribution for the possible sums when tossing two four-sided dice (the sides are numbered
alexira [117]
We would have the following sample space:
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)

Those give us these sums:
2, 3, 4, 5
3, 4, 5, 6
4, 5, 6, 7
5, 6, 7, 8

P(sum of 2) = 1/16 =0.0625
P(sum of 3) = 2/16 = 0.125
P(sum of 4) = 3/16 = 0.1875
P(sum of 5) = 4/16 = 0.25
P(sum of 6) = 3/16 = 0.1875
P(sum of 7) = 2/16 = 0.125
P(sum of 8) = 1/16 = 0.0625
8 0
3 years ago
Please solve...Thanks
liberstina [14]
Micheal has 40ft of fencing for the rectangular dog run. So the perimeter of the dog run is 40ft.

Perimeter=40ft

The perimeter of a rectangle is:

P=2l+2w

Since we know the length is 5 and the perimeter is 40, we can solve for the width.

P=2l+2w
40=2*(5)+2w
40=10+2w
subtract 10 from both sides
30=2w
divide both sides by 2
15=w

The width of the fence is 15feet.

3 0
3 years ago
The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds
boyakko [2]

The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation h=-16t^2+24t+16, where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation h=-16t^2+24t+16, we get,

0=-16t^2+24t+16

Switch sides, we have,

-16 t^{2}+24 t+16=0

Let us solve the equation using the quadratic formula.

Thus, we have,

t=\frac{-24 \pm \sqrt{24^{2}-4(-16) 16}}{2(-16)}

Simplifying, we get,

t=\frac{-24 \pm \sqrt{576+1024}}{-32}

t=\frac{-24 \pm \sqrt{1600}}{-32}

t=\frac{-24 \pm 40}{-32}

Hence, the two values of t are

t=\frac{-24 + 40}{-32}   and   t=\frac{-24 -40}{-32}

Simplifying the values, we get,

t=\frac{16}{-32}  and  t=\frac{-64}{-32}

Dividing, we get,

t=-\frac{1}{2}  and  t=2

Since, t cannot negative values, we have,

t=2

Thus, the rock will hit the ground at 2 seconds.

8 0
3 years ago
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