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zzz [600]
3 years ago
6

If f(x) = –4x2 – 6x – 1 and g(x) = –x2 – 5x + 3, find (f – g)(x).

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0

Answer:

(f – g)(x) = -3x² - x -4.

Step-by-step explanation:

Given : If f(x) = –4x² – 6x – 1 and g(x) = –x²– 5x + 3.

To find :  (f – g)(x).

Solution ; We have given that  f(x) = –4x² – 6x – 1

g(x) = –x²– 5x + 3.

(f – g)(x) = f(x) - g(x).

(f – g)(x) = (–4x² – 6x – 1 ) - ( –x²– 5x + 3) .

(f – g)(x) = –4x² – 6x – 1 + x²+ 5x - 3 .

Combine like terms

(f – g)(x) = –4x² +  x² - 6x + 5x -1 -3.

(f – g)(x) = -3x² - x -4.

Therefore,  (f – g)(x) = -3x² - x -4.

Leokris [45]3 years ago
5 0
(-4x^2 -6x -1) - (-x^2 -5x +3) = -3x^2 - x - 4
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Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

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We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

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x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

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