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Debora [2.8K]
3 years ago
14

Solve each system by elimination.3) 9x - 5y = 13- 4x + 5y = 22​

Mathematics
1 answer:
Illusion [34]3 years ago
6 0

Answer:

x=7, y=10. (7, 10).

Step-by-step explanation:

9x-5y=13

-4x+5y=22

-------------------

5x=35

x=35/5

x=7

9(7)-5y=13

63-5y=13

5y=63-13

5y=50

y=50/5

y=10

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Step-by-step explanation:

If human can eat 5% more than animal then the animal eats 5 % less than human so the answer is 5% less than human

8 0
2 years ago
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Is the given value a solution to the equation? 4(n) - 3 = -2(n) + 9 n=2
nlexa [21]

Answer:

Yes!

The solution to the equation is n = 2

Step-by-step explanation:

Given the equation

4\left(n\right)-3=-2\left(n\right)+9

remove the parentheses

4n-3=-2n+9

Add 3 to both sides

4n-3+3=-2n+9+3

Simplify

4n=-2n+12

Add 2n to both sides

4n+2n=-2n+12+2n

Simplify

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Divide both sides by 6

\frac{6n}{6}=\frac{12}{6}

Simplify

n=2

Therefore, the value of n = 2.

Hence,

Yes!

The solution to the equation is n = 2

5 0
3 years ago
What is the sum of /-10/ and /6/
kap26 [50]

Answer:

16

Step-by-step explanation:

-10 opposite is 10 which this \ or | means the its positive number. So 10 +6 is 16

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3 years ago
Tell me the answer on this to lazy at least am honest ​
luda_lava [24]

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Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
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