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3 years ago

If angle 1 measures 17x and angle 2 measures 19x then what are angle 3 and 4?

2 answers:

8 0

Here, ∠1 = ∠3 = 17x [ vertically opposite angle ]
∠2 = ∠4 = 19x [ vertically opposite angle ]

Sum of all the angles, 17x+19x+17x+19x = 360
72x = 360
x = 360/72
x = 5

So, ∠1 = ∠3 = 17(5) = 85
∠2 = ∠4 = 19(5) = 95

Hope this helps!

melomori [17]3 years ago

4 0

Angle of what shape it depends

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henry and his brother each start a savings account. henry begins with $200 and deposits $25 each month. his brother begins with

zlopas [31]

Answer:

Henry after 2 months: 250

His brother after 2 months: 220

Step-by-step explanation:

Henry started with $200 so add $25 twice (for 2 months) and get $250 dollars after 2 months.

His brother started with $150 so add $35 twice and get $220 dollars after 2 months

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3 years ago

What is the unit rate of 162 heartbeats in 60 seconds?

svetoff [14.1K]

162/60 = 2.7 heartbeats per second

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3 years ago

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Noah bought 15 baseball cards for $9.00. Each baseball card costs the same amount. How much will 12 baseball cards cost

denis-greek [22]

15 cards = 9$

1 card = (9/15)$

12 cards = 9/15 * 12

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3 years ago

Find the area bounded by the graphs of the indicated equations over the given interval.

NeX [460]

Answer:

Step-by-step explanation:

$y = 0$

is basically the horizontal axis.

First, find the integral of x^2-25.

Remember that

integral of a constant is that constant times x.

Also that

to take the integral of a power function, add 1 to the degree and divide by that same degree.

$y = {x}^{2} - 25$

We then get

$\frac{ {x}^{3} }{3} - 25x$

Evaluate at -3

$\frac{ - 3 {}^{3} }{3} - 25( - 3)$

$- 27 + 75 = 48$

Then we evaluate at 0

$\frac{0 {}^{3} }{3} - 25(0) = 0$

Next, we subtract the the answer then we get

$48 - 0 = 48$

8 0

2 years ago

1 point) Use Stoke's Theorem to evaluate ∫CF⋅dr∫CF⋅dr where F(x,y,z)=xi+yj+1(x2+y2)kF(x,y,z)=xi+yj+1(x2+y2)k and CC is the bound

Drupady [299]

Answer:

Step-by-step explanation:

Thinking process:

$\int\limits^a_b {cF} \, .dr$

= $\int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx curlFdS$ by Stoke's Theorem

= $\int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< z_x,-z_y, 1 > dA\\= \int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< 2x, 2y, 1 > dA$ since z = $25-x^{2} -y^{2} \\= 0$

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3 years ago