Step-by-step explanation:
The gender of a child which is either a boy or a girl is determined by the XX-chromosomes, or XY-chromosomes.
Since the couple plan to have 5 children, the chance of a child being a boy is equal to the chance of it being a girl - the chances are 50/50.
What we do to achieve our aim is to run a simulation that would add an X or Y to an X for all 5 children.
Doing this 125 times, we obtain the number of trials we desire.
For each trial, we get for each child, C:
C1: X + (X or Y)
C2: X + (X or Y)
C3: X + (X or Y)
C4: X + (X or Y)
C5: X + (X or Y)
Since the chance of having an X is equal to the chance of having a Y, they equal probability, which is 0.5 for each.
I think its A once again i THINK its A sorry if im wrong
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Answer:
Step-by-step explanation:
c/2-3+6/d
substitute c=14 and d=13:
14/2-3+6/13
simplify:
7-3+6/13
4+6/13
multiply 4 by 13/13 to group like terms (for a fraction):
52/13+6/13
combine:
58/13
Therefore, the answer is 58/13 or around 4.462
