1 hr = 60 minutes....so 6 hrs = (6 * 60) = 360 minutes
198 / 360 = 0.55 mousetraps per minute
no, 2 mousetraps per minute is not accurate
Answer: 0.5507
Step-by-step explanation:
Given : The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous random variable X with a cumulative distribution function

Since , the waiting time is in hours , then we can write 12 minutes as
hour i.e.0.2 hour.
Now, the probability of waiting fewer than 12 minutes between successive speeders is given by :-

Hence, the required probability = 0.5507
Answer:
a^2 - 6a + 6
Step-by-step explanation:
6−a(4−a)−2a =
6+a2+−4a+−2a
6+a2+−4a+−2a
(a^2)+(−4a+−2a)+(6)
a2+−6a+6
=a^2−6a+6
Answer:
Step-by-step explanation:
Answer:
12 + 1/10x
that would be the expression
Step-by-step explanation: