Question

A chemist makes a solution of NaOH for use in an experiment. She dissolves 0.00500 mol NaOH in 1.00 L H2O. The NaOH completely dissociates to form a solution with [OH− ] = 0.00500 M. What is the pH of the solution?

Answer 1

Answer:

pH = 11.7

Explanation:

Given:

[OH-] = 0.00500 M

To determine:

pH of the solution

Explanation:

pH refers to the H+ ion concentration in a given solution whereas pOH indicates the OH- ion concentration.

pH and pOH are related by the following equation:

$pH + pOH = 14 ------(1)$

Here:

$pH = -log[H+]\\\\pOH = -log[OH-]$

When OH- = 0.00500 M

$pOH = -log(0.00500) = 2.30$

Based on equation(1):

$pH = 14 - pOH = 14 -2.30=11.7$