When the temperature and the volume of the gas stored in the container are high then the number of the moles will be measured accurately. Thus, options A and B are correct.
<h3>What is the ideal gas law?</h3>
The ideal gas law is the establishment of the relation between the elements like the moles, pressure, temperature, and the volume of the gas containing the particle.
The ideal gas states:
PV = nRT
With an increase in the temperature, the number of particles that collides increases as the kinetic energy increases. The particle of the container is more when the volume of the gas is more.
Therefore, in options A and B high temperature and volume increase the accuracy.
Learn more about ideal gas here:
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Answer:
2.5
Explanation:
The given costs for the purchase and delivery of the cupcakes are;
The cost of 10 cupcakes and the delivery fee = $30
The cost of 25 cupcakes and the delivery fee = $67.50
Let 'c' represent the fixed cost of delivery of the cup cakes, and let 'x' represent the cost of each cup cake, we have;
30 = 10·x + c...(1)
67.50 = 25·x + c...(2)
Subtracting equation (1) from equation (2) gives;
67.50 - 30 = 37.50 = 25·x - 10·x + c - c = 15·x
∴ x = 37.50/15 = 2.5
The cost of each cupcake, x = 2.5
(∴ The delivery fee = 30 - 10 × 2.5 = 5)
The cost of each cupcake is 2.5.
Answer:
0.287 mole of PCl5.
Explanation:
We'll begin by calculating the number of mole in 51g of Cl2. This is illustrated below:
Molar mass of Cl2 = 2 x 35.5 = 71g/mol
Mass of Cl2 = 51g
Number of mole of Cl2 =..?
Mole = Mass /Molar Mass
Number of mole of Cl2 = 51/71 = 0.718 mole
Next, we shall write the balanced equation for the reaction. This is given below:
P4 + 10Cl2 → 4PCl5
Finally, we determine the number of mole of PCl5 produced from the reaction as follow:
From the balanced equation above,
10 moles of Cl2 reacted to produce 4 moles of PCl5.
Therefore, 0.718 mole of Cl2 will react to produce = (0.718 x 4)/10 = 0.287 mole of PCl5.
Therefore, 0.287 mole of PCl5 is produced from the reaction.
I'm pretty sure its an electron. I hope this helps! (: