I believe the answer is 4 carbons. Glycolysis involves break down of glucose to two molecules of pyruvic acid (3 carbons) under aerobic conditions. At the end of glycolysis the two pyruvate molecules undergoes pyruvate oxidation to capture the remaining energy in the form of ATP. A carboxyl group is removed from pyruvate and released in the form carbon dioxide, leaving a two carbon molecule which forms Acetyl-CoA (2 molecules). Acetyl-CoA then serves as a fuel for the citric acid cycle in the next stage of cellular respiration.
A.
Explanation:
Probably, if the sun was too close to the center of the galaxy, the solar system would experience chaos, such as a high frequency of collisions with other planets and stars, due to the enormous pull of the super black hole at the center of the MilkyWay Galaxy causing celestial objects to spin at very high speeds at its horizon – including bending light.
The position is postulated as the <u>Galactic habitable zone.</u>
Answer:
1.42 Kg of NaHCO3
Explanation:
From
Co= 10 pd/M
Where;
Co= concentration of the stock solution of acid
p= percentage of raw acid = 36%
d= density of the acid= 1.138g/mL
M= molar mass of the acid= 36.5 g/mol
Co= 10 × 36 × 1.138/36.5
Co= 11.22 M
Number of moles of acid= CV = 11.22 M × 1.508 L= 16.9 moles
The reaction equation is;
NaHCO3(aq)+HCl(aq)→NaCl(aq)+H2O(l)+CO2(g)
If 1 mole of NaHCO3 reacts with 1 mole of HCl
Then 16.9 moles of HCl reacts with 16.9 moles of NaHCO3
Hence 16.9 moles of NaHCO3 is required to neutralize the HCl.
From
n= m/ M
Where;
n= number of moles = 16.9
m= mass of NaHCO3= ??
M= molar mass of NaHCO3= 84.007 g/mol
m= n× M/1000
m= 16.9 × 84.007 /1000
m= 1.42 Kg
Answer:
The common application of indicators is the detection of end points of titrations. The colour of an indicator alters when the acidity or the oxidizing strength of the solution, or the concentration of a certain chemical species, reaches a critical range of values.