Answer: 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.
Step-by-step explanation:
Let X be a random variable that represents the speed of the drivers.
Given: population mean : M = 72 miles ,
Standard deviation: s= 3.2 miles
The probability that the drivers are traveling between 70 and 80 miles per hour based on this distribution:
![P(70\leq X\leq 80)=P(\frac{70-72}{3.2}\leq \frac{X-M}{s}\leq\frac{80-72}{3.2})\\\\= P(-0.625\leq Z\leq 2.5)\ \ \ \ \ [Z=\frac{X-M}{s}]\\\\=P(Z\leq2.5)-P(Z\leq -0.625)\\\\\\ =0.9938-0.2660\ \ \ [\text{Using p-value calculator}]\\\\=0.7278](https://tex.z-dn.net/?f=P%2870%5Cleq%20X%5Cleq%2080%29%3DP%28%5Cfrac%7B70-72%7D%7B3.2%7D%5Cleq%20%5Cfrac%7BX-M%7D%7Bs%7D%5Cleq%5Cfrac%7B80-72%7D%7B3.2%7D%29%5C%5C%5C%5C%3D%20P%28-0.625%5Cleq%20Z%5Cleq%202.5%29%5C%20%5C%20%5C%20%5C%20%5C%20%5BZ%3D%5Cfrac%7BX-M%7D%7Bs%7D%5D%5C%5C%5C%5C%3DP%28Z%5Cleq2.5%29-P%28Z%5Cleq%20-0.625%29%5C%5C%5C%5C%5C%5C%20%3D0.9938-0.2660%5C%20%5C%20%5C%20%5B%5Ctext%7BUsing%20p-value%20calculator%7D%5D%5C%5C%5C%5C%3D0.7278)
Hence, 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.
So we need to find the sum of the first 5 terms.
You have told me that the first term is 10 meters, and that r = 0.5 per term.
With this knowledge, we can use the formula s_n=a₁((1-r^n)/(1-r)).
Plugging in the terms that we know...
s₅=10((1-0.5⁵)/(1-0.5))
s₅=10(0.96875/0.5)
s₅=10(1.9375)
s₅=19.375
With s₅, we can determine that the ball has traveled a total of 19.375 meters after 5 bounces.
<h3>Answer: Approximately 6.4 units</h3>
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Explanation:
The origin is the point (0,0)
Use the distance formula to find the distance from (0, 0) to (4, -5)
Let
![(x_1,y_1) = (0,0)\\\\(x_2,y_2) = (4,-5)\\\\](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%20%3D%20%280%2C0%29%5C%5C%5C%5C%28x_2%2Cy_2%29%20%3D%20%284%2C-5%29%5C%5C%5C%5C)
be our two points. Plug those values into the distance formula below and use a calculator to compute
![d = \sqrt{\left(x_1-x_2\right)^2+\left(y_1-y_2\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0-(-5)\right)^2}\\\\d = \sqrt{\left(0-4\right)^2+\left(0+5\right)^2}\\\\d = \sqrt{\left(-4\right)^2+\left(5\right)^2}\\\\d = \sqrt{16+25}\\\\d = \sqrt{41} \ \text{ exact distance}\\\\d \approx 6.40312 \ \text{ approximate distance}\\\\d \approx 6.4\\\\](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cleft%28x_1-x_2%5Cright%29%5E2%2B%5Cleft%28y_1-y_2%5Cright%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%5Cleft%280-4%5Cright%29%5E2%2B%5Cleft%280-%28-5%29%5Cright%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%5Cleft%280-4%5Cright%29%5E2%2B%5Cleft%280%2B5%5Cright%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B%5Cleft%28-4%5Cright%29%5E2%2B%5Cleft%285%5Cright%29%5E2%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B16%2B25%7D%5C%5C%5C%5Cd%20%3D%20%5Csqrt%7B41%7D%20%5C%20%5Ctext%7B%20exact%20distance%7D%5C%5C%5C%5Cd%20%5Capprox%206.40312%20%5C%20%5Ctext%7B%20approximate%20distance%7D%5C%5C%5C%5Cd%20%5Capprox%206.4%5C%5C%5C%5C)
The distance between the two points (0,0) and (4,-5) is approximately 6.4 units.
Answer:x=3
Step-by-step explanation:
Equation:
5x+2=17
5x=15
x=3
That is actually true. Everything thats multiplied by 0 eaquals 0.