Answer:
The length of the segment is 10.
Step-by-step explanation:
Think of the segment as the hypotenuse of a right triangle.
Draw the legs and label the lengths.
See the picture below.
The length of the hypotenuse is c.
c^2 = a^2 + b^2
c^2 = 6^2 + 8^2
c^2 = 36 + 64
c^2 = 100
c = 10
Answer: 10
There are two triangles that exist in this problem. First is the given triangle ABC, witch AB = BC = 6 and AC = 8
Next is the smaller triangle formed by connecting points D and E; triangle EAD, with EA = AD = 3 and the length of DE is unknown.
Because these triangles are similar, a simple ratio may be set up in order to calculate DE.
DE / AC = EA / AB
DE = 3/6 * 8
DE = 4 units
If Deshawn’s goal was to raise three-fifths of $1000 you need to fond out what a fifth of 1000 is. You divide 1000 by 5 to get 200. Since it is three fifths you multiply that by 3 which equals $600. Now if Deshawn only reached five-sixths of $600 you need to find out what a sixth of 600 is so divide 600 by 6 which equals 100. Now you multiply that by five as it is 5 sixths of the goal which equals $500. So the answer would be - Deshawn raised $500.
A chemist plans to mix 10 liters of a 40% acid solution with some 70% to obtain a 50% solution
40% = 0.4
70% = 0.7
50% = 0.5
A chemist plans to mix 10 liters of a 40%. So 10 times of 0.4 = 4
Let x be the some amount of solution of 70%
70% of x = 0.7x
chemist obtain a 50% of solution
Amount of mixture is 10 + x
So 10+x of 50% = (10+x)*0.5
Now we frame an equation
10 * 0.4 + x * 0.7 = (10+x) * 0.5
4 + 0.7x = 5 + 0.5x
Subtract 4 and 0.5x on both sides
0.2 x= 1
Divide by 0.2
So x= 5
5 liters of 70% of solution is used.