Answer:
c=10(g+5)
Step-by-step explanation:
Given that,
The cost of customer smartphone bill is given by the equation as follows :
c=10g+50
Where
g is the number of gigabits of data the customer per month
We need to factor this cost polynomial
The common between 10 and 50 is 10
Taking 10 common. So,
c=10(g+5)
Hence, the required factor is equal to c=10(g+5).
Answer: the amount of dimes is $1.15 this is also equivalent to 11 dimes and an extra nickel.
Explanation:
80 nickels =$4.00
$5.15-$4.00= $1.15
11 dimes= $1.10
1 nickel= $0.05
$1.10+$0.05= $1.15
hope this helps! :)
The value of x in the algebraic equation is: -5/2.
<h3>How do you Find the Value of a Variable in an Algebraic Equation?</h3>
Given an algebraic equation, to find the unknown value of x, solve by isolating x in the equation.
Given:
4x + 26 = 16
Subtract 26 from both sides
4x = 16 - 26
4x = -10
Divide both sides by 4
x = -10/4
x = -5/2
Therefore, the value of x in the algebraic equation is: -5/2.
Learn more about algebraic equation on:
brainly.com/question/2164351
Answer:
D
Step-by-step explanation:
you have to multiply .79 to both a and 1.2. A is wrong because it's saying we need to multiply .79 to 1.2lb. which is the weight of oranges and the total cost of apples and oranges which is 6.27.
Answer:
The 95% confidence interval is 
Step-by-step explanation:
From the question we are told that
The sample size is n = 48
The sample mean is 
The standard deviation is 
Now given that the confidence level is 95% , then the level of significance is mathematically represented as
Next we obtain the critical value of 
from the normal distribution table , the value is
The reason we are obtaining critical values of
instead of 
is because
represents the area under the normal curve where the confidence level interval (
) did not cover which include both the left and right tail while
is just the area of one tail which what we required to calculate the margin of error
The margin of error is mathematically represented as
substituting values
The 95% confidence interval to estimate the mean breaking weight for this type cable is mathematically evaluated as
substituting values
