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crimeas [40]
4 years ago
13

you have reading homework every 6 days and you have science homework every 15 days. If you have homework in both today when will

you have homework in both subjects on the same day again?
Mathematics
1 answer:
cluponka [151]4 years ago
8 0
Do you remember when you were learning about the "Least Common
Multiple" of two numbers, and you were wondering why you had to learn
it, because you were so sure that you'd never need to use it ?  Do you
remember that ?

Well, HERE's where you get to use it.  This question is just looking for
the LCM of 6 and 15 .  THAT's how many days it will be before you get
homework in both subjects on the same day again.

(It's not 90 days, and it's not 60 days.)
You might be interested in
Pearl's Biking Company manufactures and sells bikes. Each bike costs £40 to make, and the company's fixed costs are £5000. In ad
____ [38]

Answer:

R(x) =300·x - 2·x²

C(x) = £5000 + £40 × x

The break even points are 23.47 and 106.53 or 23 and 107 bikes

Step-by-step explanation:

Given that the price function P(x) = 300 -2·x

Cost per bike = £40

The revenue function R(x) is given by  bike price × total number of bikes manufactured and sold

∴ R(x)  = P(x)×x = (300 - 2·x)×x = 300·x - 2·x²

The company's cost function, C(x) is Fixed cost + cost to produce each bike × total number of bikes produced

∴ C(x) = £5000 + £40 × x

The break even point is given by the relation;

Total revenue - total cost = 0

That is, break even point is R(x) - C(x) = 0

300·x - 2·x² - (5000 + 40·x) = 0

-2·x²+260·x-5000 = 0 or 2·x²- 260·x + 5000 = 0

Factorizing, we have;

(x - (65 -5√69))(x - (65 +5√69))

Solving gives x = 23.47 or 106.53

Therefore, the break even points are 23.47 and 106.53.

That is the company is profitable when they produce less than 23 bikes or more than 107 bikes.

3 0
3 years ago
An ancient Roman coin is found and a curious anthropologist wishes to determine if the coin is fair— Fair meaning that when flip
Mamont248 [21]
The coin wouldn't be fair, because it landed on heads 72/100 times. If the coin was fair, the results should be equivalent to 1/2.
7 0
3 years ago
Read 2 more answers
Integrate x+1/sqrt(x). I know that the answer is 2/3 • sqrt(x) • (x+3) + C, but I don't know how it is simplified from 2/3 • x^3
Andreas93 [3]

\displaystyle\int\frac{x+1}{\sqrt x}\,\mathrm dx=\int\frac x{x^{1/2}}+\frac1{x^{1/2}}\,\mathrm dx

=\displaystyle\int x^{1/2}+x^{-1/2}\,\mathrm dx

By the power rule,

=\dfrac{x^{3/2}}{\frac32}+\dfrac{x^{1/2}}{\frac12}+C

(this seems to be the step you're not getting?)

=\dfrac23x^{3/2}+2x^{1/2}+C

The next step is to pull out a common factor of x^{1/2} from the antiderivative:

x^{3/2}=x^{1/2+1}=x^{1/2}\cdot x^1

so that the final result is

\dfrac23x^{3/2}+2x^{1/2}+C=\dfrac23x^{1/2}(x+3)+C

3 0
3 years ago
the 2008 year book at middleton middle school had 236 candid pictures of students. the 2007 yearbook had 214 candid pictures of
Nostrana [21]
Use proportions.
214/236=x/100(100 because it's a percentage.
cross multiply:
23600=214x
solve for x:
x= 11.3(rounded)
11.3% increase
4 0
3 years ago
Consider a standard deck of 52 playing cards with 4 suits. If A is the event of drawing a 6 from the deck, and B is the event of
crimeas [40]

Answer: Intersection of A and B = 2

Step-by-step explanation:

Total cards = 52

Let A is the event of drawing a 6 from the deck, and B is the event of drawing a black playing card from the deck.

Total cards having 6 on them = 4

[There are 4 suits of two different colors red and black.]

Total  black playing card =26

Intersection of A and B = Black cards having 6 = 2

hence, Intersection of A and B = 2

8 0
3 years ago
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