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Arte-miy333 [17]
3 years ago
7

Which expression is equivalent to 5x+3?​A. 8xB. 3+5xC. 3x+5D. 5(x+3)

Mathematics
2 answers:
MariettaO [177]3 years ago
6 0

Answer:

B

Step-by-step explanation:

lyudmila [28]3 years ago
6 0
B is equivalent to 5x+3
the reason to this is because 3 and 5 are just switched
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What’s the equation for the order pairs (1,-5) and (-2,5)
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\bf \begin{array}{|c|ll}&#10;\cline{1-1}&#10;\textit{point-slope form}\\&#10;\cline{1-1}&#10;\\&#10;y-y_1=m(x-x_1)&#10;\\\\&#10;\cline{1-1}&#10;\end{array}\implies y-(-5)=-\cfrac{10}{3}(x-1)\implies y+5=-\cfrac{10}{3}x+\cfrac{10}{3}&#10;\\\\\\&#10;y=-\cfrac{10}{3}x+\cfrac{10}{3}-5\implies y=-\cfrac{10}{3}x-\cfrac{5}{3}

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2 years ago
Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

7 0
2 years ago
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