Which equation has the same solution as x^2-6x-14
2 answers:
So,
First, notice that all of the answer options are in completed square form. So all we have to do is complete the square for the initial equation and see which equation it matches.
Isolate the constant term.
Add the necessary amount to both sides (halve the x term and square it).
Factor the completed square.
This equation is identical to the equation in option B.
The correct answer is B.
First, notice that all of the answer options are in completed square form. So all we have to do is complete the square for the initial equation and see which equation it matches.
Isolate the constant term.
Add the necessary amount to both sides (halve the x term and square it).
Factor the completed square.
This equation is identical to the equation in option B.
The correct answer is B.
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First you have to find the intercepts!
To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~
To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~