Answer:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Step-by-step explanation:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
i think the answer is 1.6*10^-3
Step-by-step explanation:
Answer:
1) the quadrants go counter clockwise, Quadrant I is the upper right square, Quadrant II is the upper left square, Quadrant III is the lower left square, and Quadrant IV is the lower right square.
2) Quadrant II
3) Quadrant IV
4) Quadrant III
5) Quadrant I
6) Both would be on the horizontal axis
7) Both would be on the vertical axis
Step-by-step explanation:
Hope this helped!
Answer:
f(x)=12x
Step-by-step explanation
We know that f(x) is our y-coordinate and x is the x-coordinate
Next we should insert x-6 as x in the equation
This is f(x)=12(x-6)-72
But if you look at this that leads to 12x-72 (ignore y-intercept)
That is our first equation
This means that if you take out -6 from the x
You will get f(x)=12x
(Also do you go to RSM?)
