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Sidana [21]
2 years ago
7

If y=4x+5 how much does the tree grow each year?

Mathematics
2 answers:
goldenfox [79]2 years ago
8 0

Answer: Tree dont grow.....You must water.. The graphing points are (-1,0) (0,5) I think

Elena L [17]2 years ago
6 0

Answer:

4 ( not sure what the units are)

Step-by-step explanation:

Just by looking at the slope you can figure out how much it grows per year.

y = mx + b

m = slope

Not sure what units there are in the question just place it in the end.

Hope this helps :)

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2. 4/6 , 6/9
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6 0
3 years ago
It is estimated % of all adults in United States invest in stocks and that % of U.S. adults have investments in fixed income ins
katovenus [111]

Complete question :

It is estimated 28% of all adults in United States invest in stocks and that 85% of U.S. adults have investments in fixed income instruments (savings accounts, bonds, etc.). It is also estimated that 26% of U.S. adults have investments in both stocks and fixed income instruments. (a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places. (b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

Answer:

0.929 ; 0.306

Step-by-step explanation:

Using the information:

P(stock) = P(s) = 28% = 0.28

P(fixed income) = P(f) = 0.85

P(stock and fixed income) = p(SnF) = 26%

a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places.

P(F|S) = p(FnS) / p(s)

= 0.26 / 0.28

= 0.9285

= 0.929

(b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?

P(s|f) = p(SnF) / p(f)

P(S|F) = 0.26 / 0.85 = 0.3058823

P(S¦F) = 0.306 (to 3 decimal places)

3 0
3 years ago
Simplify(4-x) (7+x) <br>​
Sophie [7]

(4-x) ( 7+ ×)

28 +4x -7x -x²

28 -3x - x²

7 0
3 years ago
7.15z + 2.3z = ?z i hate math
Nitella [24]

Answer:

9.45z :)

Step-by-step explanation:

3 0
2 years ago
32​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
Tems11 [23]

Answer:

a) P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

b) P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

c) P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.32)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

Part b

P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]

P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211  

P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

Part c

P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264

P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218

P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123

P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

6 0
3 years ago
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