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makkiz [27]
3 years ago
15

Based on the graph, is there an association between

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0

Answer: There is an association because the distribution of correct guesses is the same among the mint groups.

Step-by-step explanation:

We would have to see the graph but I know it's either B or C because the other answer choices don't make sense. I chose B because it seems like the most logical choice of the two.

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8 0
3 years ago
What does the linear inequality y ≥ −x − 3 look like?
kupik [55]
It is a line that divides the space into two.. The line is y=-x-3
8 0
3 years ago
Find the value of csc theta, if cos =-3/5; 90 degrees < theta < 180 degrees
Sloan [31]

Answer:\frac{5}{4}

Step-by-step explanation:

Given

\cos \theta =\frac{-3}{5}

and \theta  lies between

90^{\circ}

and for this \theta,\sin and \text{cosec} is Positive as they lie in 2 nd Quadrant

\sin ^2\theta +\cos ^2\theta =1

\sin ^2\theta =1-(\frac{-3}{5})^2

\sin ^2\theta =1-\frac{9}{25}

\sin ^2\theta =\frac{16}{25}

\sin \theta =\frac{4}{5}

\therefore \text{cosec}\ \theta =\frac{5}{4}

6 0
3 years ago
The midpoint of AB is M(3, -1). If the coordinates of A are (5,1), what are the
Vera_Pavlovna [14]

Given parameters:

Midpoint of AB =  M(3, -1)

Coordinates of A = (5,1)

Unknown:

Coordinates of B = ?

Solution:

To find the mid point of any line, we use the expression below;

              x_{m}   = \frac{x_{1} + x_{2}  }{2}    and y_{m}  = \frac{y_{1} + y_{2}  }{2}

where x_{m}  and y_{m} = coordinates of the mid points = 3 and -1

   x₁  = 5 and y₁ = 1

  x₂ = ?  and y₂ = ?

Now let us input the variables and solve,

            3  = \frac{5 + x_{2} }{2}           and     -1 = \frac{1 + y_{2} }{2}

    5 +  x₂  = 6                          -2 = 1  + y₂

            x₂ = 1                             y₂ = -2 -1 = -3

The coordinates of B = 1, -3

6 0
3 years ago
Bx^(2)+2b^(2)-b^(3)-2x^(2)
8090 [49]

Answer:

(b+x)(−b+x)(b−2)

Step-by-step explanation:

Factor bx2 + 2b2 − b3 − 2x2  − b3 + bx2 + 2b2 − 2x2  = (b+x)(−b+x)(b−2)

hope this helps! :)

8 0
3 years ago
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