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tekilochka [14]
3 years ago
6

The measure of an angle is 6 less than 5 times its complement. what is the measure of its complement

Mathematics
2 answers:
ra1l [238]3 years ago
8 0
Measure of angle is 6 less than 5 times its complement,
Equation is:
A= 5 x (90 - A) - 6
Solve for A.
A=5(90-A)-6
A=450-5A-6
Add 5A to both sides
6A=444
A=74°
Now the complementary angle=90°-74° =16°


Answer: 16°
pogonyaev3 years ago
4 0

Answer:

the measure of its complement is 16\°

Step-by-step explanation:

Let

x-----> the measure of an angle

y----> the measure of the complement of angle x

we know that

x+y=90\° ----> equation A

x=5y-6 -----> equation B

Substitute equation B in equation A

5y-6+y=90

Solve for y

5y+y=90+6

y=96/6=16\°

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Step-by-step explanation:

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\sec^2(\theta) = (\sec(\theta))^2

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Where:

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So:

\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2

\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2

\sec^2(\theta) = (\sqrt{82})^2

\sec^2(\theta) = 82

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\cot(\theta)

This is calculated as:

\cot(\theta) = \frac{1}{\tan(\theta)}

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\tan(\theta) = 9 ---- given

So:

\cot(\theta) = \frac{1}{\tan(\theta)}

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Solving (c):

\cot(\frac{\pi}{2} - \theta)

In trigonometry:

\cot(\frac{\pi}{2} - \theta) = \tan(\theta)

Hence:

\cot(\frac{\pi}{2} - \theta) = 9

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\csc^2(\theta)

This is calculated as:

\csc^2(\theta) = (\csc(\theta))^2

\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2

Where:

\sin(\theta) = \frac{Opposite}{Hypotenuse}

\sin(\theta) = \frac{9}{\sqrt{82}}

So:

\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2

\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2

\csc^2(\theta) = \frac{82}{81}

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