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Volgvan
3 years ago
12

PLZZZ SEND HELPPP ANSWER QUICKK

Mathematics
2 answers:
madreJ [45]3 years ago
8 0

Answer:

2^3

Step-by-step explanation:

Ok, let's jump right in!

Multiply 2^6 by 2^−3 by adding the exponents.

Use the power rule a^m a^n = a^m+n to combine exponents. Therefore, we get:

2^ 6-3

Subtract 3 from 6.

2^3

TIP: For next time remember that when you have to multiply exponents you that have the same base number you really just have to add the exponents.

EastWind [94]3 years ago
4 0

Answer:

The answer is C 2^3

hope this helps!!!

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Which of the following types of statements can justify the steps of a proof?
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A quantity with an initial value of 600 decays exponentially at a rate of
Snowcat [4.5K]

Answer:

The value of the quantity after 87 months will be of 599.64.

Step-by-step explanation:

A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.

This means that the quantity, after t periods of 6 years, is given by:

Q(t) = 600(1 - 0.0005)^{t}

What is the value of the quantity after 87 months, to the nearest hundredth?

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So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).

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8 0
3 years ago
F divides HJ in the ratio 3:1. If H = (-11,7) and J = (5,3), what are the<br> coordinates of F?
Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) =  (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

l_{HF} = \sqrt{\left (4-7  \right )^{2}+\left (1-(-11)  \right )^{2}} = \sqrt{\left (-3  \right )^{2}+\left (12  \right )^{2}} = 3\cdot \sqrt{17}

Similarly, we check the length of HJ, to get;

l_{HF} = \sqrt{\left (3-7  \right )^{2}+\left (5-(-11)  \right )^{2}} = \sqrt{\left (-4  \right )^{2}+\left (16  \right )^{2}} = 4\cdot \sqrt{17}

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

7 0
3 years ago
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