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Ket [755]
3 years ago
9

What are some physical means of separating something?

Chemistry
1 answer:
Alika [10]3 years ago
3 0
Mixtures come in many forms and phases. Most of them can be separated, and the kind of separation method depends on the kind of mixture it is. Below are some common separation methods:
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The process by which cells chemically break down small food molecules and release chemical energy for the cell’s use is called
Crazy boy [7]

Answer: HEY THERE!

Explanation: HERE IS YOUR ANSWER

Cellular respiration is what happens inside cells when they use oxygen to transfer energy from food to ATP. Cellular respiration is essential to the transfer of matter and energy through living systems

<em>HOPE THIS HELPED AND HAVE A NICE DAY!</em>

5 0
3 years ago
Read 2 more answers
What happens to the mass of substances during a physical change?
Anna [14]

Here are the answers in order:

1. During a physical change the substance changes physically.

2. The law of conservation of mass is a law stating the conservation of mass cannot be higher than 46mg or lower than 32mg.

3. A hypothesis is a guess that you make before completing a science experiment, it can be considered a law because it is important to know why you are making the guess.

4. During a chemical change the mass is changing colors. This is a representation of a chemical change.

5. Oil is a non-renewable resource, so it cannot demonstrate the conservation of mass.

6. When the color of the substance has changed or when it explodes.

7. Reactants are the objects that react when in a chemical change.

8. If you follow the rule of not going higher than 46mg and not lower than 32mg then it will automatically follow this law.

Chemical Reactions Part One Video:

1. mass

2. erupt-ant

3. reactant

4. object

5. mixtures

6. molecules

7. color changed

Questions again:

1. A chemical reaction

2. A physical change

3. Because if it is no higher than 46mg and no lower than 32mg then it will follow on it's own.

8 0
3 years ago
Read 2 more answers
A basketball weighs approximately 1.35 kg. What is this mass in grams (g)?<br><br> step by step
choli [55]

Answer:

1350 g

Explanation: just add a 0

8 0
2 years ago
Hi guys, my question is:
guapka [62]

Answer:

See Explanation Below

Explanation:

A) The rate law can only be on the reactant side and you can only determine it after you get the net ionic equation because of spectators cancelling out. So in this case the rate law is k=[CH3Br]^1 [OH-]^1. The powers are there because the rxn is first order.  

B) Since the rxn is first order anything you do to it will be the exact same "counter rxn" per say so since you are decreasing the OH- by 5 the rate will decease by 5

C) The rate will increase by 4 since you are doubling both you have to multiply them both.

8 0
2 years ago
Use this equation for the following problems: 2NaN3 --&gt; 2Na+3N2
olchik [2.2K]

Answer:

1) 65.0

2) 16.434 L = 16434 mL.

Explanation:

<em>2NaN₃ → 2Na + 3N₂,</em>

  • It is clear from the balanced equation that 2.0 moles of NaN₃ are decomposed to 2.0 moles of Na and 3.0 moles of N₂.

<em>Q1: How many grams of NaN₃ are needed to make 23.6L of N₂?​ </em>

Density of N₂ = 0.92 g/L which means that every 1.0 L of N₂ contains 0.92 g of N₂.

  • Now, we can get the mass of N₂ in 23.6 L N₂ using cross multiplication:

1.0 L of N₂ contains → 0.92 g of N₂.

23.6 L of N₂ contains → ??? g of N₂.

∴ The mass of N₂ in 23.6 L of N₂ = (23.6 L)(0.92 g)/(1.0 L) = 21.712 g.

  • We can get the no. of moles of 23.6 L of N₂ (21.712 g) using the relation:

n = mass/molar mass = (21.712 g)/(28.0 g/mol) = 0.775 mol.

  • We can get the no. of moles of NaN₃ needed to produce 0.775 mol of N₂:

<em><u>using cross multiplication:</u></em>

2.0 moles of NaN₃ produce → 3.0 moles of N₂, from the balanced equation.

??? mol of NaN₃ produce → 0.775 moles of N₂.

∴ The no. of moles of NaN₃ needed = (2.0 mol)(0.775 mol)/(3.0 mol) = 0.517 mol.

  • Finally, we can get the grams of NaN₃ needed:

<em>mass = no. of moles x molar mass</em> = (0.517 mol)(65.0 g/mol) =<em> 33.6 g.</em>

<em />

<em>Q2: How many mL of N₂ result if 8.3 g Na are also produced?</em>

  • We need to get the no. of moles of 8.3 g Na using the relation:

n = mass/atomic mass = (8.3 g)/(22.98 g/mol) = 0.36 mol.

  • We can get the no. of moles of N₂ produced with 0.36 mol of Na:

<em><u>using cross multiplication:</u></em>

2.0 moles of Na produced with → 3.0 moles of N₂, from the balanced equation.

0.36 moles of Na produced with → ??? moles of N₂.

∴ The no. of moles of N₂ needed = (3.0 mol)(0.36 mol)/(2.0 mol) = 0.54 mol.

  • We can get the mass of 0.54 mol of N₂:

mass = no. of moles  x molar mass = (0.54 mol)(28.0 g/mol) = 15.12 g.

  • Now, we can get the mL of 15.12 g of N₂:

<em><u>using cross multiplication:</u></em>

1.0 L of N₂ contains → 0.92 g of N₂, from density of N₂ = 0.92 g/L.

??? L of N₂ contains → 15.12 g of N₂.

<em>∴ The volume of N₂ result </em>= (1.0 L)(15.12 g)/(0.92 g) = <em>16.434 L = 16434 mL.</em>

4 0
2 years ago
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