Will the boiling point of water be higher or lower in the maintains, where the altitude is high, and the pressure is low ?

Solutions of potassium iodide and lead(II)nitrate are mixed. The resulting lead

LenaWriter [7]

Answer is D
Balance the equation

6 0

2 years ago

What is the volume (in liters) occupied by 49.8 g og HCl at STP

Anon25 [30]

Using ideal gas equation,

P\times V=n\times R\times T

Here,

P denotes pressure

V denotes volume

n denotes number of moles of gas

R denotes gas constant

T denotes temperature

The values at STP will be:

P=1 atm

T=273 K

R=0.0821 atm L mol ⁻¹

Mass of HCl given= 49.8 g

Molar mass of HCl given=36.41

Number of moles of gas, n= \frac{Given mass of the substance}{Molar mass of the substance}

Number of moles of gas, n= \frac{49.8}{36.46}

Number of moles of gas, n= 1.36

Putting all the values in the above equation,

V=\frac{1.36\times 0.0821\times 273}{1}

V=30.6 L

So the volume will be 30.6 L.

6 0

2 years ago

An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit

Anon25 [30]

<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol

<u>Explanation:</u>

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of triprotic acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL$

Putting values in above equation, we get:

$3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M$

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

$0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol$

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

7 0

2 years ago

. The speed of a sound in air is 343 m/s. The sound wave has a frequency of 436 HZ and its period is 0.0023 s. What is the wavel

Taya2010 [7]

Answer: 0.79

Explanation:

6 0

2 years ago

Nitrous oxide gas is a form of

zepelin [54]

Its a form of anaesthesia used by dentists

hope that helsp

6 0

2 years ago