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4 years ago

HURRY ! the BEST I will give the brainliest ! Show you solution

Chemistry

1 answer:

omeli [17]4 years ago

6 0

Vi = 0

Vf = 15

time = 8

a = ?

Vf = Vi + (a × time)

15 = 0 + (a × 8)

15 = 8a

Divide both side

Then a = 1.88 (rounded off)

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When was helium discoved?

andrey2020 [161]

It was discovered in 1868.i hope this helps you .

4 0

3 years ago

Does boron or lithium have a greater first ionization energy ?

Leni [432]

Answer:

beryllium has a higher ionization energy because its radius is smaller. boron has a higher ionization energy because its radius is smaller.

7 0

3 years ago

There are 342 g of sucrose in 1.00 mol of sucrose. What is the molar concentration (molarity) of a solution containing 171 g suc

AVprozaik [17]

For the answer to the question above, use these formulas in solving your problem and as a guide.

MM = 342 (g/mol) 

171 (g) / 342(g/mol) = x mol of sucrose 
x moles of sucrose/ 1.25 L = Molarity of soultion

I hope I helped you with your problem. Have a beautiful day!

7 0

3 years ago

Which of the following solutions is a good buffer system?A solution that is 0.10 M HCN and 0.10 M NaClA solution that is 0.10 M

patriot [66]

Answer:

A solution that is 0.10 M HCN and 0.10 M LiCN

Explanation:

A good buffer system contains a weak acid and its salt or a weak base and its salt.
In this case; A solution that is 0.10 M HCN and 0.10 M LiCN, would make a good buffer system.
HCN is a weak acid, while LiCN is a salt of the weak acid, that is, CN- conjugate of the acid.

8 0

3 years ago

Cars run on gasoline, where octane (C8H18) is the principle component. This combustion reaction is responsible for generating en

Bezzdna [24]

Answer:

10.19 g CO₂

4.69 g H₂O

Explanation:

The combustion reaction of Octane is:

C₈H₁₈ → 8CO₂ + 9H₂O

To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.

We calculate the mass of Octane from the given volume and density, using the following conversion factors:

1 gallon = 3.785 L

1 L = 1000 mL

Now we convert 1.24 gallons to mL:

1.24 gallon * $\frac{3.785L}{1gallon} *\frac{1000mL}{1L} =$ 4693.4 mL

We calculate the mass of Octane:

4693.4 mL * 0.703 g/mL = 3.30 g Octane

Now we use the stoichiometric ratios and molecular weights to calculate the mass of CO₂ and H₂O:

CO₂ ⇒ 3.30 g Octane ÷ 114g/mol * $\frac{8molCO_{2}}{1molOctane}$ * 44 g/mol = 10.19 g CO₂

H₂O ⇒ 3.30 g Octane ÷ 114g/mol * $\frac{9molH_{2}O}{1molOctane}$ * 18 g/mol = 4.69 g H₂O

7 0

4 years ago

HURRY ! the BEST I will give the brainliest​ ! Show you solution

HURRY ! the BEST I will give the brainliest ! Show you solution