Answer: please find attached to see the structure.
1. THE STRUCTURE OF BENZOIC ACID AND FLUORENE, soluble in ether and insoluble in water.
2. THE STRUCTURE OF CARBOXYLIC ACID BEEN EXTRACTED.
Explanation: the mixture of benzoic acid and fluorene are the first diagrams which shows the carboxylic acid attached to the benzene ring, which are soluble in ether and insoluble in water. When dissolved in NaOH(aq) is the carboxy ion becomes soluble in water but insoluble in ether, this is seen in the second diagram.
The third diagram shows the carboxylic acid been precipitated and soluble in ether but insoluble in water.
NOTE THE TWO MAIN DIAGRAM IS THE FIRST AND THE LAST DIAGRAM, WHERE CARBOXYLIC ACID DISSOLVES IN AQUEOUS SODIUM HYDROXIDE, AND WHEN THE ACID IS BEEN PRECIPITATED IN AQUEOUS HCl.
ALSO NOTE THE CHANGE IN BENZOIC RING MIXED WITH FLUORENE TO THAT OF THE ACID BEEN EXTRACTED.
Hope together with the picture, this has helped you.
B= CH2O
empirical formula using the simplest ratio of atoms in the compound
Answer:
3.72 mol Hg
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Density = Mass over Volume
Explanation:
<u>Step 1: Define</u>
D = 13.6 g/mL
54.8 mL Hg
<u>Step 2: Identify Conversions</u>
Molar Mass of Hg - 200.59 g/mol
<u>Step 3: Find</u>
13.6 g/mL = x g / 54.8 mL
x = 745.28 g Hg
<u>Step 4: Convert</u>
<u />
= 3.71544 mol Hg
<u>Step 5: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
3.71544 mol Hg ≈ 3.72 mol Hg
Concentration is the number of moles of solute in a fixed volume of solution
Concentration(c) = number of moles of solute(n) / volume of solution (v)
25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.
original solution molarity - 0.150 M
number of moles of LiOH in 1 L - 0.150 mol
number of LiOH moles in 0.125 L - 0.150 mol/ L x 0.125 L = 0.01875 mol
when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases
new volume - 125 mL + 25 mL = 150 mL
therefore new molarity is
c = 0.01875 mol / 0.150 L = 0.125 M
answer is 0.125 M
