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Zina [86]
2 years ago
9

PLEASE HELP >.<

Mathematics
2 answers:
Makovka662 [10]2 years ago
8 0

Answer:

what that guy said

Step-by-step explanation:

belka [17]2 years ago
4 0
Check the picture below.

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0.27 x 0.03 PLEASE EXPLAIN THE ANSWER! HOW DID YOU GET THE SUM??<br><br><br> I NEED HELP PLEASE!
kow [346]
It would be 0.008 because you line up the decimals and multiply
8 0
3 years ago
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Tito drives his car and covered a distance of 225 kilometers in 7.5 hours. What is the average in kilometers per hour?
Eva8 [605]

Step-by-step explanation:

I hope u are asking for average speed

average speed = total distance/total time

= 225/7.5

= 30 km/h or 30 km per hour

6 0
2 years ago
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Plsss help me !!!!
Yuri [45]

Answer:

The enrollment after 5 years is 10,724

Step-by-step explanation:

Generally, we can have the depreciation formula written as follows;

A = P(1 - r)^t

A is the number of enrollment in after a certain number of years t

P is the initial population which is 13,500

r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045

t = 5 years

Substituting these values, we have it that;

A = 13,500(1-0.045)^5

A = 10,723.84

4 0
2 years ago
Need the answer to the question
Morgarella [4.7K]

Answer:

The graph is wider and is reflected across the x axis.

Step-by-step explanation:

See attached image.

5 0
2 years ago
the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.
suter [353]

Answer:

The width of the photo is 4w^2+6w+4.

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

6w^2+8

The photo is covered by a frame border and the width of the border is

w^2-3w+2

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})

\text{Width of the photo}=6w^2+8-2(w^2-3w+2)

\text{Width of the photo}=6w^2+8-2w^2+6w-4

\text{Width of the photo}=4w^2+6w+4

Therefore the width of the photo is 4w^2+6w+4.

4 0
2 years ago
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