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Sav [38]
2 years ago
7

In the year 2015 Emily was three times as old asKaitlin. By the year 2021 Kaitlin will be half asold as Emily will be. How old w

as Emily on theyear 2000?
Mathematics
1 answer:
weeeeeb [17]2 years ago
8 0

In 2000 Emily was 9 years old.

Given that in the year 2015 Emily was three times as old as Kaitlin while by the year 2021 Kaitlin will be half as old as Emily will be, to determine how old was Emily on the year 2000 the following calculation must be performed:

  • 2015 = E = 3K
  • 2021 = E = 2K  
  • 24 /// 8 --- 30 /// 14
  • 18 /// 6 --- 24 /// 12
  • 18/6 = 3
  • 24/12 = 2
  • 2015 = Emily was 24 years old
  • 24 - (2015 - 2000) = X
  • 24 - 15 = X
  • 9 = X

Therefore, in 2000 Emily was 9 years old.

Learn more in brainly.com/question/20025195

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3. A dish contains 100 candies. Juan removes candies from the dish each day and no
iVinArrow [24]

Answer:

11

Step-by-step explanation:

If i am correct n= the days so with the days adding up day 10 juan would have 55 of the 100 candies, day 11 he would have 66. The statement said at least 64, so it would have to be 64 or the closet amount to 64 but it cannot be lower than 64. So there for 66 is the closest to the given amount, and in order for juan to get 64 he would need to take candies out for 11 days.

7 0
2 years ago
What’s the answer to the question
hammer [34]
A maybe? I don’t know honestly
6 0
3 years ago
How many lines of symmetry does a regular decagon have?<br><br> 8<br><br> 10<br><br> 11<br><br> 12
bixtya [17]
The number of sides is the same as the number of lines of symmetry and the order of rotational symmetry.

So, a regular decagon would have 10 lines of symmetry.
6 0
3 years ago
Read 2 more answers
How many 5-digit palindromes contain only even digits?
34kurt

Answer:

The correct answer is - 900

Step-by-step explanation:

A palindrome is a positive integer that is same whether read from left to right or from right to left. For example, 123321 palindromes.

An n-digit palindrome is determined from the first  n/2  digits if n is even, and from the first n+1/2 digits if n is odd.

Therefore, if  n  is even, there are  9×10⁽n⁻²/²⁾  palindromes; and if n is odd, there are  9×10⁽n₋²/²⁾ palindromes.  where n is number of digits.

For  n=5 , there are  9×10²=900 palindromes

3 0
3 years ago
In a particular lottery, 5 winning numbers are drawn from a set of 37 numbers. What is the probability of picking exactly 2 of t
anygoal [31]

Since 5 winning numbers are draw and there are exactly 2 winning numbers, the other 3 numbers chosen have to be incorrect.

The 2 numbers picked right, there are 5C2=10 different possibilities.

The other 3 numbers are just picked from the rest of the 32 numbers. Getting there are 32C3=4960 different possibilities.

For each set of 2 correct winning numbers, you could have the 4960 different losing numbers to match up to make a unique set. This meant that there are 4690*10=46900 different total possibilities.

Now the total different outcomes of how you can choose the numbers are 37C5=435897 outcomes.

Now the way to find probabilities is want/total

The want is 46900 and the total is 435897

Doing the division you get the number rounded to the nearest thousandths as   0.107 or in percent form as

10.759% chance of picking exactly 2 winning numbers.

This seems like a competition problem of some sort therefore I assume that you already know what combinations in form nCk and permutation in form nPk means.

8 0
2 years ago
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