Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
40= 1,2,4,5,8,10,20,40
48= 1,2,3,4,6,8,12,16,24,48
the gcf is 8.
In the situation '<span>Each letter of the English alphabet is written on a scrap of paper and put in a hat p(j)= 1/26', the type of probability illustrated is classical or mathematical probability. This is because 1 represents the number of expected outcomes of the event while 26 represents the total number of outcomes.</span>
So easy so easy so easy so easy so easy so easy so easy 9
We have
that
Cost
use of a backhoe----------------------$300 an hour
<span> Estimate for equipment rental each week---------------------$18,400</span>
Total
hours operator per week--------------------------------------40
<span> 40*300</span>=$12000---------------------it
is the cost per week to use a backhoe
$12000<$18400 is ok
<span> The maximum of hours that I can rent </span>a backhoe <span> are 40 hours, since it is the limit of the
operator and it do not overcome the total budget </span>
