Answer:

Step-by-step explanation:
We want to find a third degree polynomial with zeros <em>x </em>= 2 and <em>x</em> = 2i and f(-1) = 30.
First, note that by the Complex Root Theorem, since <em>x</em> = 2i is a root, <em>x</em> = -2i must also be a root.
Hence, we will have the three factors:

Where <em>a</em> is the leading coefficient.
Expand and simplify the second and third factors:

Hence:

Since f(-1) = 30:

In conclusion, third degree polynomial function is:

Answer:
b/a
Step-by-step explanation:
Given,(b^-2)/a*(b^-3)
or,(b^-2+3)/a
or,b/a
Answer:
x - 11
Step-by-step explanation:
Let f(x) = -5x - 4 and g(x) = 6x - 7.
f(x) + g(x)
I like to line them up vertically
-5x - 4
6x - 7
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x-11