4 years ago

How many solutions will the following equation have? 25=20x-4x^2

1 answer:

lisabon 2012 [21]4 years ago

3 0

Hello,

$4x^2-20x+25=0\\

\Delta=20^2-4*4*25=0\\

x= \dfrac{20}{8} = \dfrac{5}{2} \\

4x^2-20x+25=0\\

(2x-5)^2=0\\

\mbox{One solution (double) Sol=\{ \dfrac{5}{2} \}}


$

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