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aniked [119]
3 years ago
11

How many solutions will the following equation have? 25=20x-4x^2

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0
Hello,

4x^2-20x+25=0\\

\Delta=20^2-4*4*25=0\\

x= \dfrac{20}{8} = \dfrac{5}{2} \\

4x^2-20x+25=0\\

(2x-5)^2=0\\

\mbox{One solution (double) Sol=\{ \dfrac{5}{2} \}}



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Is (5,15) a solution of the equation y= 3x? (plz answer asap)
sashaice [31]

Answer:

Yes

Step-by-step explanation:

15 = 3(5)

15 = 15

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6 0
3 years ago
Limit as x approaches 0 of csc3x/cotx
jolli1 [7]
Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.

For instance, we can find the lim by using the number -.00001 for x and solve
<span>csc(3x) / cot(x)
</span>csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3

We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
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<span>\lim_{x\to 0} \frac{csc(3x)}{cot(x)} = \frac{1}{3}</span>

6 0
3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
7.) x-3&gt;4 please help
givi [52]

Answer:

x>7

Step-by-step explanation:

x-3>4

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x>7

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