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Alona [7]
3 years ago
15

I really need help with this question , can someone help me?

Mathematics
1 answer:
Alexxx [7]3 years ago
8 0
I'm too late but here ya go anyway :)

x = 180 - (31 + 40) is the answer.
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Evaluate each expression for the given value(s) of the variables(s).
masya89 [10]

Answer:

9.  \frac{1}{10,000} = 0.0001

10. \frac{1}{81}

Step-by-step explanation:

9. x^{-4}

Evaluate when x = 10.

Substitute x = 10 into the expression

10^{-4}

Apply the negative exponent rule (a^{-n} = \frac{1}{a^n})

Thus:

= \frac{1}{10^4}

= \frac{1}{10^4} = \frac{1}{10,000} = 0.0001

10. 2a^{-1}b^{-3}

Evaluate when a = 6 and b = 3

Substitute

(2*6^{-1})(3^{-3})

Apply the negative exponent rule

(2*\frac{1}{6})(\frac{1}{3^3})

(\frac{2}{6})(\frac{1}{27})

\frac{2*1}{6*27}

\frac{1}{81}

8 0
3 years ago
Read 2 more answers
Give the formula for a function with domain (5, ∞) that has the following properties:
KATRIN_1 [288]

Answer:

The area under the curve y = f(x) at x-axis, on the interval x E (5, ∞) is equal to 7.

Step-by-step explanation:

Solution

Given that:

f(x) = 7√x-5

The function of domain is:

D = x-5 > 0

x>5

so,

x← (5, ∞)

Now,

(1) The sequence root function is always known as positive, i.p defined from x E (5, ∞)

i.p =√x-5

Thus,

7/√x-5 >0

Therefore f(x) = 7/√√x-5 which is a positive integer, which is defined in domain x E (5, ∞).

Each value exist a real and unique values of f(x)

Now,

The function f(x) is continuous and over the interval(5, ∞)

Note: Kindly find an attached copy of part to the solution of this given question below

7 0
3 years ago
Use the zeros of the following quadratic to find the x value ​
Artyom0805 [142]

Answer:

A

Step-by-step explanation:

x^2 - 4x +3

(x - 1)(x-3)

x = 1, x = 3

3 0
3 years ago
How do u graph linear inequality
amm1812
There are three steps

1 rearrange the equation so "y" is on the left and everything else is on the right

2 plot the "y=" line (make it a solid line for y< or y> and a dashed line for y< or y>)

3 shade above the line for a "greater than" (y> or y>) line under that or below the line for a less than (y< or y< line under it)
6 0
3 years ago
Heya!
dimulka [17.4K]

Answer:

the answer is in last picture

6 0
3 years ago
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