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4 years ago

A dog uses 30 lbs of dog food per day. How many pounds are used in a year?

1 answer:

6 0

To solve this we would do 30×365

We would do this because each day the dog 30lbs

So we have the equation y=30x
Where y= total amount of dog food
And x= number of days

In a year there are 365 days typically, so we do 30×365

30×365=10,950

In one year 10,950 lbs of dog food are used

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Answer: 19

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3 years ago

Complete the solution table from left to right for the quadratic function. (I did not select an answer, that was a mistake) Than

Karo-lina-s [1.5K]

Answer: OPTION D

Step-by-step explanation:

To complete the table, you need to substitute the values of "x" given in the table into the quadratic equation $y=x^{2}-x-6$ to obtain the corresponding value of "y".

Then:

When $x=-5$ :

$y=(-5)^{2}-(-5)-6$

$y=24$

When $x=-3$ :

$y=(-3)^{2}-(-3)-6$

$y=6$

When $x=-1$ :

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$y=-4$

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8 0

4 years ago

Please help me with the following (1-5)

Ivanshal [37]

$1. \: 405352 \: cm = 4.05352 \times {10}^{5} \: cm$

___o___o___

2. 7.6352 x 10-3 kg ( This is scientific notation) [ If you want —> Standard notation]

7.6352 x 10^ -3 kg = 0.0076352 kg

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$3. \: \: 3.1 \times 10 ^{4} mm + 4.87 \times {10}^{5} \: mm \\ 0.31\times 10 ^{4} mm + 4.87 \times {10}^{5} \: mm \\ = 5.18 \times {10}^{5} \: mm$

____o___o___

$4. \: \: (4.8 \times {10}^{5} \: km) \times (2.0 \times {10}^{3} \: km ) \\ = 9.6 \times {10}^{8} \: km$

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$5.(3.3 \times{10}^{ - 4}\: ml)\div(1.1 \times {10}^{ - 6}\: ml) \\ \\ \frac{3.3 \times {10}^{ - 4} \: ml}{1.1 \times {10}^{ - 6} \: ml} = \frac{33 \times {10}^{ - 4} \: ml}{11 \times {10}^{ - 6} \: ml} \\ \\ = \frac{33 \times {10}^{ - 4 + 6} }{11} ml \\ \\ = 3 \times {10}^{2} \: ml$

I hope I helped you^_^

6 0

3 years ago

Can you slove this please

Ket [755]

Answer:

y=85°

p=100°

Step-by-step explanation:

Corresponding Angles Theorem

Alternate Exterior Angles Theorem

7 0

3 years ago

She needs to buy at least 100 chairs. Chairs with arms cost $80. Chairs without arms cost $70. Ms. Robinson can spend, at most,

stealth61 [152]

Answer:

50 chairs with arms and 50 without arms will cost $7500

Step-by-step explanation:

Create two equations using the given information. The unknowns are :

W = Number of chairs with arms

N = Number of chairs with No arms

First equation (associated with the total number of chairs to buy):

W + N = 100

Second equation (associated with the amount to spend):

80 W + 70 N = 7500

Solving: solve for W in the first equation: W = 100 - N

Use it to substitute for W in the second equation:

80 (100 - N) + 70 N = 7500

8000 - 80 N + 70 N = 7500

subtract 8000 from both sides and combine

- 10 N = - 500

Divide both sides by -10 in order to solve for N

N = -500 / (-10) = 50

Now use this value in the substitution equation to solve for W:

W = 100 - 50 = 50

So the person can buy 50 chairs with arms and 50 chairs without arms paying for them $7,500.

8 0

3 years ago