G solve 2x 00 + 10x = 3u(t − 12) − 5δ(t − 4) with x(0) = −1 and x 0 (0) = −2.
1 answer:
<span>{2 x×0 + 10 x = 3 u(t - 12) - (5 δ(t - 4)) x(0) = -1, x×0×0 = -2}
</span><span>{10 x = 3 u(t - 12) - 5 x(0) δ(t - 4) = -1, False}</span>
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