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Gekata [30.6K]
3 years ago
6

G solve 2x 00 + 10x = 3u(t − 12) − 5δ(t − 4) with x(0) = −1 and x 0 (0) = −2.

Mathematics
1 answer:
vekshin13 years ago
8 0
<span>{2 x×0 + 10 x = 3 u(t - 12) - (5 δ(t - 4)) x(0) = -1, x×0×0 = -2}

</span><span>{10 x = 3 u(t - 12) - 5 x(0) δ(t - 4) = -1, False}</span>
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c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx  = 1

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c\int\limits^3_0 {\frac{xy^{2}}{2}  +\frac{xy^{3}}{3} } \, dx (0,3}) = 1

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c\int\limits^3_0 {(\frac{x* 3^{2}}{2}  +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2}  +\frac{x * 0^{3}}{3})} \, dx = 1

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Add fraction

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Rewrite;

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Multiply both sides by \frac{12}{729}

c    =  \frac{12}{729}

c    =  0.0165 (Approximately)

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