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3 years ago

What is -8/12 in decimal form

Mathematics

1 answer:

Degger [83]3 years ago

3 0

-0,666666666666666666666667

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Two binomials that are factors of x^2+8x+12

alina1380 [7]

Answer:

(x+2) (x+6)

Step-by-step explanation:

x^2+8x+12

What 2 numbers multiply together to give you 12 and add together to give you 8

2*6 = 12

2+6 = 8

(x+2) (x+6)

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3 years ago

Tossing a coin and spinning a spinner with five equal sections, 1-5

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Answer:

Its gonna be a 50/50 on the coin and 20/100 chance for the spinner

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How do you find a rate of a number

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To determine the rate of a number do the following steps:

Multiply the number by the percent (e.g. 87 * 68 = 5916)

Divide the answer by 100 (Move decimal point two places to the left) (e.g. 5916/100 = 59.16)

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Draw apicture to show how many hundreds there are in 1 thousand

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4 years ago

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A tank contains 60 kg of salt and 1000 L of water. A solution of a concentration 0.03 kg of salt per liter enters a tank at the

charle [14.2K]

Answer:

$\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg$

Step-by-step explanation:

Volume of water in the tank = 1000 L

Let y(t) denote the amount of salt in the tank at any time t.

Initially, the tank contains 60 kg of salt, therefore:

y(0)=60 kg

Rate In

A solution of concentration 0.03 kg of salt per liter enters a tank at the rate 9 L/min.

$R_{in}$ =(concentration of salt in inflow)(input rate of solution)

$=(0.03\frac{kg}{liter})( 9\frac{liter}{min})=0.27\frac{kg}{min}$

Rate Out

The solution is mixed and drains from the tank at the same rate.

Concentration, $C(t)=\dfrac{Amount}{Volume} =\dfrac{y(t)}{1000}$

$R_{out}$ =(concentration of salt in outflow)(output rate of solution)

$=\dfrac{y(t)}{1000}* 9\dfrac{liter}{min}=0.009y(t)\dfrac{kg}{min}$

Therefore, the differential equation for the amount of Salt in the Tank at any time t:

$\dfrac{dy}{dt}=R_{in}-R_{out}\\\\\dfrac{dy}{dt}=0.27-0.009y(t),$ y(0)=60kg$

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4 years ago