Answer:
Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A
Explanation:
Let the depth of each section is h.
That means the real depth for each section is h.
Apparent depth is liquid A is 7 cm.
Apparent depth in liquid B is 6 cm.
Apparent depth in liquid C is 5 cm.
by the formula of the refractive index
n = real depth / apparent depth
where, n is the refractive index of the liquid.
For liquid A:
.... (1)
For liquid B:
..... (2)
For liquid C:
..... (3)
By comparing all the three equations
nc > nB > nA
Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A
Answer:
ok my brudda this makes no sense are you trying to fart or take a dump like what do you mean "increase the particle motion of a gas" sound like you need to take a massive dump or a massive fart so its bbc big black you know what saying
Explanation:
because its a bbc .
Answer:
F = 3750 N
Explanation:
Given that,
Pressure, P = 150 Pa
Area, a = 25m²
We need to find the force applied. We know that, pressure is equal to the force acting per unit area. It can be given by :
So, the required force is 3750 N.
Answer:
M = 6.32 x 10⁻⁶ H
Explanation:
given,
Length of solenoid = 10 cm = 0.1 m
diameter = 0.40 cm
radius = 0.2 cm = 0.002
number of turns, N₁ = 800
N₂ = 50
mutual inductance will be equal to
M = 6.32 x 10⁻⁶ H
hence, mutual inductance of the combination of two coil is equal to M = 6.32 x 10⁻⁶ H
For the position of button we can use force balance as
Friction Force = Centripetal force
so here we will have
here we know that
R = radius of circle where button is placed
f = 35 rev/min
now from above equation
so friction coefficient will be 0.33
