Answer:
See below
Explanation:
Normal force = m g cos 53 = 8 kg * 9.8 m/s^2 * cos 53 = 47.1823 N
no work is done by this force
Force friction = coeff friction * force normal = .4 * 47.1823 = 7.55 N
work of friction = 7.55 * 2 m = 15.1 j
Force Downplane = mg sin 53 = 62.61 N
work = 62.61 * 2 = 125.22 j
Net Force downplane = force downplane - force friction = 55.06 N
net Work = force * distance = 55.06 N * 2 M = 110.12 j
because water is loosely packed but when it is cold it becomes closely packed in order to form ice and thus the force attraction between them also increase.
Answer:
Power= 6.84×10⁸ W
Explanation:
Given Data
Niagara falls at rate of=1.4×10⁶ kg/s
falls=49.8 m
To find
Power Generated
Solution
Regarding this problem
GPE (gravitational potential energy) declines each second is given from that you will find much the kinetic energy of the falling water is increasing each second.
So power can be found by follow
Power= dE/dt = d/dt (mgh)
Power= gh dm/dt
Power= 1.4×10⁶ kg/s × 9.81 m/s² × 49.8 m
Power= 6.84×10⁸ W
Answer:
A true
Explanation:
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