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laila [671]
3 years ago
14

A ball is connected to a light spring suspended vertically. When pulled downward from its equilibrium position and released, the

ball oscillates up and down. In the system of the ball and the spring, what forms of energy are there during the motion?
Physics
1 answer:
babunello [35]3 years ago
5 0

Answer:

The forms of energy involved are

1. Kinetic energy

2. Potential energy

Explanation:

The system consists of a ball initially at rest. The ball is pulled down from its equilibrium position (this builds up its potential energy) and then released. The released ball oscillates due to a continuous transition between kinetic and potential energy.

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What is general relativity
juin [17]
General relativity is a theory of space and time. The theory was published by Albert Einstein in 1915. The central idea of general relativity is that space and time are two aspects of spacetime. Spacetime is curved when there is gravity, matter, energy, and momentum.
5 0
3 years ago
Describe the responses of the human ear to sound waves coming from the
maria [59]

If the sound comes from the right side, the waves reach the right ear before the left ear. if the sound comes from the left side, the waves reach the left ear before the right ear. The difference between the phases of waves reaching both ears is detected by the ears and then interpreted by the brain

8 0
3 years ago
What is the current through a 11v bulb with a power of 99w
Murrr4er [49]

Answer:

9.01amp

Explanation:

Power = V^2/R

Given that v = 11volts, P = 99watts

99 = 11^2/R

11×11 = 99R

121= 99R

R = 121/99

R= 1.22ohms

From ohms Law; V = IR

11volts = I × 1.22ohms

I = 11/1.23

I = 9.01 amp

8 0
3 years ago
The express train can travel 100 miles per hour. This information describes the train'sAnsweracceleration.direction.speed.veloci
solmaris [256]
Velocity because it gives the displacement and time
3 0
4 years ago
A light, rigid rod is 55.8 cm long. Its top end is pivoted on a frictionless horizontal axle. The rod hangs straight down at res
VMariaS [17]

To solve this problem we will apply the principle of conservation of energy. For this purpose, potential energy is equivalent to kinetic energy, and this clearly depends on the position of the body. In turn, we also note that the height traveled is twice that of the rigid rod, therefore applying these concepts we will have

KE = PE

\frac{1}{2} mv^2 = mgh

v = \sqrt{2gh}

v = \sqrt{2(9.8)(2(55.8*10^{-2}))}

v = 4.67m/s

Therefore the minimum speed at the bottom is required to make the ball go over the top of the circle is 4.67m/s

4 0
3 years ago
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