Answer:
Vertically
Explanation:
Pressure changes faster as we move vertically because as we go to the height from the surface of the earth. The density of air becomes lesser in comparison with the surface of the earth. So, as we move vertically pressure moves faster than in comparison with the vertical movement.
The best example that describes the above statement is the hill station.
Answer:
9.39 m/s
Explanation:
Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.
Assume the up direction is positive and the down direction is negative.
- v₀ = 0 m/s
- a = -9.8 m/s²
- Δy = -50 m
- t = ?
Find the constant acceleration equation that contains these four variables.
Substitute known values into this equation.
Multiply and simplify.
Divide both sides of the equation by -4.9.
Square root both sides of the equation.
Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.
List out known variables in the x-direction.
- v₀ = ?
- t = 3.194382825 s
- a = 0 m/s²
- Δx = 30 m
Find the constant acceleration equation that contains these four variables.
Substitute known values into the equation.
- 30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²
Multiply and simplify.
Divide both sides of the equation by 3.194382825.
The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.
Answer:
It is due to the large impulse is imparted on the flour.
Explanation:
A ball is moving faster.
When a ball is moving faster strikes to the flour, the change in momentum is large and thus the impulse imparted on the flour is large.
Impulse = change in momentum
So, as the flour experiences large impulse and large momentum so that the flour spreads out.
If the change in momentum is large so the flour spreads out is more.
(a) The final velocity if the trucks lock together after the collision is 7.66 m/s.
(b) The decrease in the kinetic energy after the collision is 11,165.1 J.
<h3>
Conservation of linear momentum</h3>
The final velocity of the two truck system after the collision is determined by applying the principle of conservation of linear momentum as shown below;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
4285(9.35) + 5495(6.35) = v(4285 + 5495)
74,958 = 9,780v
v = 74,958/9780
v = 7.66 m/s
<h3>Initial kinetic energy of the trucks</h3>
K.E = ¹/₂mv²
K.Ei = ¹/₂(4285)(9.35)² + ¹/₂(5495)(6.35)²
K.Ei = 298,088.78 J
<h3>Final kinetic energy of the trucks</h3>
K.Ef = ¹/₂(m₁ + m₂)v²
K.Ef = ¹/₂(4285 + 5495)(7.66)²
K.Ef = 286,923.68 J
<h3>Change in kinetic energy</h3>
ΔK.E = K.Ef - K.Ei
ΔK.E = 286,923.68 J - 298,088.78 J
ΔK.E = - 11,165.1 J
Learn more about linear momentum here: brainly.com/question/7538238
