1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Montano1993 [528]
4 years ago
5

C= 5/9 (F−32) The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured i

n degrees Celsius. Based on the equation, which of the following must be true? I. A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 5/9 degree Celsius. II. A temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit. III. A temperature increase of 5/9 degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius. A) I only B) II only C) III only D) I and II only
Physics
1 answer:
iren [92.7K]4 years ago
7 0

Answer:

option d) is correct

Explanation:

Given:

C = (5/9)(F-32)

For statement I

C = (5/9)F - (5/9)32

let the initial temperature in Fahrenheit  be 0

thus,

C = (5/9)(0) - (5/9)32 = - (5/9)32

for 1° increase in Fahrenheit

we get

C = (5/9)(1) - (5/9)32 = 1 - (5/9)32

thus,

on comparing the results, statement I is true

now for statement II

let the initial temperature in Celsius  be 0

thus,

0 = (5/9)(F) - (5/9)32

or

F =  (9/5)(5/9)32 = 32

for 1° increase in Celsius

we get

1 = (5/9)(F) - (5/9)32

or

(5/9)F = 1 + (5/9)32

or

F = (9/5) + 32

or

F = 1.8 + 32

thus,

on comparing the results, statement II is true

Now, for statement III

let the initial let the initial temperature in Fahrenheit  be 0

thus,

C = (5/9)(0) - (5/9)32 = - (5/9)32 = - 17.77

for (5/9)° increase in Fahrenheit

we get

C = (5/9)(5/9) - (5/9)32 = (0.3086) - 17.77 = -17.469

thus,

on comparing the results, statement III is false

Hence, option d) is correct

You might be interested in
Redox reactions: Redox reactions: rarely involve enzymes. do not occur under physiological conditions. are characterized by one
Gnoma [55]

Answer:

are characterized by one substance gaining an electron while another substance loses an electron

Explanation:

Redox reaction in chemical reaction in which one substance gaining an electron while another substance loses an electron. This means that one element is oxidize by losing an electron while the other is reduced by gaining an electron. The one oxidized is called reducing agent while the one reduced is called oxidizing agent.

8 0
3 years ago
It has been claimed that an insect called the froghopper (Philaenus spumarius) is the best jumper in the animal kingdom. This in
Vladimir [108]

Answer:

v=4m/s

Explanation:

The formulas for accelerated motion are:

v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}

We can derive the formula v^2=v_0^2+2ad from them.

We have:

v-v_0=at\\t=\frac{v-v_0}{a}

And substitute:

x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}\\2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2

Where in the first step of the last row we just multiplied everything by 2a. Since x-x_0 is the displacement d, we have proved that v^2=v_0^2+2ad

We use then our values to calculate the final velocity when starting from rest, traveling a distance 0.002m with acceleration 4000 m/s^2:

v=\sqrt{v_0^2+2ad}=\sqrt{2(4000m/s^2)(0.002m)}=4m/s

7 0
3 years ago
You and your friends are doing physics experiments on a frozen pond that serves as a frictionless, horizontal surface. Sam, with
Misha Larkins [42]

Answer:

Sam's and Abigail speeds before colliding were a. 12.34 m/s and b. 2.86 m/s, respectively. Their total kinetic energy was diminished by c. 1484.42 J, approximately

Explanation:

By conservation of momentum, we have

\Delta \vec{p} = 0\\\\m\vec{v}_i = m\vec{v}_f\\m_S v_S\hat{i} + m_A v_A\hat{j} = m_S \times 7 \cos{(40)} \hat{i} + m_S \times 7 \sin{(40)} \hat{j} + m_A \times 9.4 \cos{(18)} \hat{i} - m_A \times 9.4 \sin{(18)} \hat{j}.

Writing for each direction at a time,

m_S v_S = 7m_S \cos{(40)} +9.4 m_A \cos{(18)}\\v_S = 7 \cos{(40)} + 9.4 \frac{m_A}{m_S} \cos{(18)} = 7 \cos{(40)} + 9.4\times\frac{57}{73} \cos{(18)} \approx \mathbf{12.34}\\m_A v_A = 7m_S\sin{(40)} - 9.4m_A\sin{(18)}\\v_A = 7\frac{m_S}{m_A}\sin{(40)} - 9.4\sin{(18)} = 7\times\frac{73}{57}\sin{(40)} - 9.4\sin{(18)} \approx \mathbf{2.86}.

Their kinetic energy changed by

K_f - K_i = \left( \frac{1}{2}m_s v_{fs}^2 + \frac{1}{2}m_a v_{fa}^2 \right) - \left( \frac{1}{2}m_s v_{is}^2 + \frac{1}{2}m_a v_{ia}^2 \right) =  \left( \frac{1}{2}\times 73 \times 7^2 + \frac{1}{2}\times 57 \times 9.4^2 \right) - \left( \frac{1}{2}\times 73 \times 12.34^2  + \frac{1}{2}\times 57 \times 2.86^2 \right) \approx \mathbf{-1484.418 J}.

3 0
3 years ago
What is the formula and measure of each of these?
Bingel [31]

the symbol of mass is similar to meter but actually it is different,ve careful

8 0
4 years ago
Ruff, the 50 cm tall Labrador Retriever stands 3 m from a plane mirror and looks at his image. What is Ruff’s image position and
sertanlavr [38]
Since the mirror is plane, the image will be formed behind the mirror. The distance will be the same as that of the distance of the object from the mirror and the height will just be the same.
So, Ruff's image will be 3 m behind the mirror and 50 cm tall.
8 0
3 years ago
Other questions:
  • HELP RIGHT NOW THE RIGHT ANSWER GETS BRAINLEST!!!
    15·2 answers
  • If a sprinter’s mass is 60 kg, how much forward force must be exerted on the sprinter to make the sprinter accelerate at 0.8 m/s
    12·2 answers
  • A heat engine takes in 840 kJ per cycle from a heat reservoir. Which is not a possible value of the engine's heat output per cyc
    15·1 answer
  • In which case would a widely accepted scientific idea most likely be revised?
    9·2 answers
  • Which is an example of a screw? Lightbulb,ladder,screwdriver,flag pole
    8·1 answer
  • How thick is Earth's crust?
    15·1 answer
  • The graph below shows the speed of a car as it drives along a racetrack.
    6·1 answer
  • an unknown charge exerts an attractive force of 4.23 E 13 N. If these charges are separated by 8cm, what is the magnitude of the
    14·1 answer
  • A population _____ follows a period of
    8·2 answers
  • at Niagara Falls, if 505 kg of water fall a distance of 50.0 m, what is the increase in the internal energy of the water at the
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!