2 years ago

I forgot how to do this!! i'd like help please!!

Mathematics

1 answer:

user100 [1]2 years ago

3 0

Answer:

9) 28

10) 22

Step-by-step explanation:

collinear means on the same line

9 ) AB+BC=AC

16+12=28

10) 13+9=22

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Solve for w: k = 3pw<br> please help i have no clue

navik [9.2K]

Answer:

$w = \dfrac{k}{3p}$

Step-by-step explanation:

k = 3pw

Step 1: switch sides.

3pw = k

Step 2: Since you want w alone, and w is being multiplied by 3p, divide both sides by 3p.

$w = \dfrac{k}{3p}$

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3 years ago

What does x+7=2 what does x mean

Ksenya-84 [330]

Answer:-5

Step-by-step explanation:

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2 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

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3 years ago

Expresión factorizada <br> 12abxyz - 3xyz - 4 ab + 1

BARSIC [14]

Answer:

12+3-4+1=12

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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