Ask question

Ask question

All categories

denis-greek [22]

2 years ago

8

I forgot how to do this!! i'd like help please!!

1 answer:

user100 [1]2 years ago

3 0

Answer:

9) 28

10) 22

Step-by-step explanation:

collinear means on the same line

9 ) AB+BC=AC

16+12=28

10) 13+9=22

You might be interested in

If 5,142 x 679= 3,491, then 51.42 x 67.9

nirvana33 [79]

Answer:

3.491

Step-by-step explanation:

move the decimal over 3 places.

5 0

3 years ago

What is the length? In algebra DUE TOMORROW

Mamont248 [21]

The formula for volume is V=lhw, or length times height times weight. To find the length, you divide the volume by the height and width.

In this case, divide 3,060 first by 12, the height, then by 15, the width.

3,060/12=255
255/15=17

The length is 17.

8 0

3 years ago

6. Let f and g be differentiable functions

Julli [10]

Answer:

(b) 1

Step-by-step explanation:

To differentiate $h(x)=f(x)g(x)$ we will need the product rule:

$h'(x)=f'(x)g(x)+f(x)g'(x)$ .

We have $h'(x)=f(x)g'(x)$ , so the following equation is true by the transitive property:

$f'(x)g(x)+f(x)g'(x)=f(x)g'(x)$

By subtraction property we have:

$f'(x)g(x)=0$

Since $g(x) \neq 0$ , then we can divide both sides by $g(x)$ :

$f'(x)=\frac{0}{g(x)}$

$f'(x)=0$

This implies $f(x)$ is constant.

So we have that $f(x)=c$ where $c$ is a real number.

Since $f(0)=1$ and $f(0)=c$ , then by transitive property $1=c$ .

So $f(x)=1$ .

Checking:

$h(x)=1 \cdot g(x)$

$h'(x)=g'(x)=1 \cdot g'(x)$

So the following conditions were met.

5 0

3 years ago

F(x) = 2-4<br> Find f(2)

Jet001 [13]

Answer:

-8

Step-by-step explanation:

So first off, x is 2-4. So that's the default. It would be -2. If you multiply -2 by 2, it is -4.

8 0

9 months ago

I need help please and thank you

Setler [38]

12.57 m sq hope that helps

5 0

2 years ago