Answer:
(m−5)(2m−2)
=(m+−5)(2m+−2)
=(m)(2m)+(m)(−2)+(−5)(2m)+(−5)(−2)
=2m2−2m−10m+10
=2m2−12m+10
Answer:
800 bacteria
Step-by-step explanation:
Answer of this question depend upon number of hours at the end of day
Let Take Full Day of 24 hrs
Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)
Colby bacteria at end of day = 50 * 2¹²
Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)
Let say Jaquan bacteria at start of Day = J
Jaquan bacteria at end of day = J * 2⁸
Equating Both
J * 2⁸ = 50 * 2¹²
=> J = 50 * 2⁴
=> J = 50 * 16
=> J = 800
Jaquan will start with 800 Bacteria
When x is zero there will never be an interception of the line as x=0 is an asymtope
It should be (2x-3)x(3x+2)
