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dimulka [17.4K]
3 years ago
8

In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.

Mathematics
2 answers:
REY [17]3 years ago
5 0

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

Sauron [17]3 years ago
3 0
The answers 
1)  <span>D. (TRANSITIVE PROPERTY OF CONGRUENCY)
2)  </span><span>C. (LINEAR PAIR THEOREM)
3)  </span><span>D. TRANSITIVE PROPERTY OF CONGRUENCY) to equations (1) and (2), we get m∠IKL + m∠JLD = 180°.
4)  </span><span>C. (CONGRUENT SUPPLEMENTS THEOREM)</span>
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Step-by-step explanation:

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Find the x-intercept and y-intercept of the line. <br> 3x + 5y = −15
insens350 [35]

Answer:

The x intercept  is (-5,0)

The y intercept  is (0,-3)

Step-by-step explanation:

To find the x intercept we set y=0 and solve for x

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3x+0 = -15

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Divide by 3

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To find the x intercept we set x=0 and solve for y

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3 years ago
Given the m∠5 = 45°, find the measure of ∠8.
Colt1911 [192]

Answer:

  (c)  135°

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Angles 5 and 8 form a linear pair, which means they are supplementary: their measures total 180°.

  ∠8 = 180° -∠5 = 180° -45°

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3 years ago
A construction crew must build 3 miles of road. On tuesday, they build 1/4 mile of road. How many miles of road do they still ha
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Answer:

2.25 miles of road they have to build this week

Step-by-step explanation:

Given:

Total distance of the road = 3 miles

Distance constructed on Tuesday = 1/4 mile of road.

To Find:

Miles of road still have to be built this week=?

Solution:

Let the Distance that have  to be built be X

Then,  

X= total distance of the Road – the distance built on Tuesday

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X = 3 - \frac{3}{4}

X =\frac{12 -3}{4}

X= \frac{ 9}{4}

X= 2.25  miles

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