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dimulka [17.4K]
2 years ago
8

In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.

Mathematics
2 answers:
REY [17]2 years ago
5 0

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

Sauron [17]2 years ago
3 0
The answers 
1)  <span>D. (TRANSITIVE PROPERTY OF CONGRUENCY)
2)  </span><span>C. (LINEAR PAIR THEOREM)
3)  </span><span>D. TRANSITIVE PROPERTY OF CONGRUENCY) to equations (1) and (2), we get m∠IKL + m∠JLD = 180°.
4)  </span><span>C. (CONGRUENT SUPPLEMENTS THEOREM)</span>
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Nataliya [291]

Answer:

You may or may not need to include the units.

A = 18x - 18

P = 6x + 6

Graph is attached below. (2, 18)

Step-by-step explanation:

Substitute the information we need, "l" and "w", into the formulas.

l is for length, 6cm.

w is for width, (3x - 3)cm.

Use the formula for area of a rectangle.

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P = 2(l + w)

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P = (6x + 6)cm  or 6x + 6

Linear equations are written in the form y = mx + b, so we do not need to factor or further simplify the formulas.

To graph, first turn the "m" value into a fraction form.

8 -> 8/1

6 -> 6/1

You need two points to graph each line.

For each equation, the first point is on the y-axis at the "b" value. Then use the "m" in the equation to count the number of units up (numerator) and to the right (denominator).

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8 0
3 years ago
Decomponha os seguintes números a) 1.585 = b) 1.059= c) 2.440 d) 5.329 e) 8.801 f) 9.999 g) 3.718 h) 6.840 i) 7.504 j) 5.225 1)
vlada-n [284]

Answer:

a) 1.585 =1.0 + 0.5+ 0.08+0.005

b) 1.059= 1 .0+ 0.0+ 0.05+0.009

c) 2.440 = 2.0 + 0.4+ 0.04

d) 5.329= 5.0 + 0.3+ 0.02+0.009

e) 8.801 = 8.0 + 0.8+ 0.00+0.001

f) 9.999= 9.0 + 0.9+ 0.09+0.009

g) 3.718 = 3.0 + 0.7+ 0.01+0.008

h) 6.840= 6.0 + 0.8+ 0.04

i) 7.504 = 7.0 + 0.5 +0.004

j) 5.225 = 5.0 + 0.2+ 0.02+0.005

1) 4.063 = 4.0 + 0.0+ 0.06+0.003= 4+0.06+0.003

m) 2.597= 2 .0+ 0.5+ 0.09+0.007

Step-by-step explanation:

A medida que nos alejamos del punto decimal, el número de ceros aumenta y el dígito se mueve hacia la derecha.

Los valores después del decimal se denominan décimas, centésimas y milésimas.

a) 1.585 =1.0 + 0.5+ 0.08+0.005

b) 1.059= 1 .0+ 0.0+ 0.05+0.009

c) 2.440 = 2.0 + 0.4+ 0.04

d) 5.329= 5.0 + 0.3+ 0.02+0.009

e) 8.801 = 8.0 + 0.8+ 0.00+0.001

f) 9.999= 9.0 + 0.9+ 0.09+0.009

g) 3.718 = 3.0 + 0.7+ 0.01+0.008

h) 6.840= 6.0 + 0.8+ 0.04

i) 7.504 = 7.0 + 0.5 +0.004

j) 5.225 = 5.0 + 0.2+ 0.02+0.005

1) 4.063 = 4.0 + 0.0+ 0.06+0.003= 4+0.06+0.003

m) 2.597= 2 .0+ 0.5+ 0.09+0.007

The values after the decimal are called tenths hundredths and thousandths

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sergeinik [125]

Answer:

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